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Honors Geometry Section 5.2 Use Perpendicular Bisectors.

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Presentation on theme: "Honors Geometry Section 5.2 Use Perpendicular Bisectors."— Presentation transcript:

1 Honors Geometry Section 5.2 Use Perpendicular Bisectors

2 Perpendicular Bisector A segment, ray, line, or plane that is perpendicular to a segment at its midpoint.

3 Equidistant A point that is the same distance from each figure. Points on the perpendicular bisector of a segment are equidistant from the segment’s endpoints.

4 THEOREM 5.2Perpendicular Bisector Theorem In a plane, if a point is on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment. If is the  bisector of, then CA = CB.

5 THEOREM 5.3Converse: Perpendicular Bisector Theorem In a plane, if a point is equidistant from the endpoints of a segment, then it is on the perpendicular bisector of the segment. If DA = DB, then D lies on the  bisector of.

6 EXAMPLE 1 Use the Perpendicular Bisector Theorem AD = CD Perpendicular Bisector Theorem 3x + 14 5x =5x = 7 x = BD is the perpendicular bisector of AC. Find AD. AD = 5x = 5(7) = 35. ALGEBRA

7 EXAMPLE 2 Use perpendicular bisectors SOLUTION a. WX bisects YZ, so XY = XZ. Because W is on the perpendicular bisector of YZ, WY = WZ by Theorem 5.2. The diagram shows that VY = VZ = 25. In the diagram, is the perpendicular bisector of a. What segment lengths in the diagram are equal?

8 EXAMPLE 2 Use perpendicular bisectors b. Is V on WX ? b. Because VY = VZ, V is equidistant from Y and Z. So, by the Converse of the Perpendicular Bisector Theorem, V is on the perpendicular bisector of YZ, which is WX. In the diagram, is the perpendicular bisector of

9 Concurrent When three or more lines, rays, or segments intersect in the same point. Point of Concurrency The point of intersection of the lines, rays, or segments.

10 THEOREM 5.4Concurrency of Perpendicular Bisectors of a Triangle The perpendicular bisectors of a triangle intersect at a point that is equidistant from the vertices of the triangle. If are perpendicular bisectors, then PA = PB = PC.

11 EXAMPLE 3 Use the concurrency of perpendicular bisectors FROZEN YOGURT Three snack carts sell frozen yogurt from points A, B, and C outside a city. Each of the three carts is the same distance from the frozen yogurt distributor. Find a location for the distributor that is equidistant from the three carts.

12 EXAMPLE 3 Use the concurrency of perpendicular bisectors Theorem 5.4 shows you that you can find a point equidistant from three points by using the perpendicular bisectors of the triangle formed by those points.

13 EXAMPLE 3 Use the concurrency of perpendicular bisectors Copy the positions of points A, B, and C and connect those points to draw ∆ ABC. Then use a ruler and protractor to draw the three perpendicular bisectors of ∆ ABC. The point of concurrency D is the location of the distributor.

14 The point of concurrency of the three perpendicular bisectors of a triangle. The circumcenter P is equidistant from the three vertices, so P is the center of a circle that passes through all three vertices. Circumcenter

15 The location of P depends on the type of triangle.


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