1. Torque is a twisting force. It’s magnitude is r x F. Where r is the “moment arm” or distance to the axis of rotation. You can increase torque by just increasing the moment arm. This is how many tools (levers, wrenches) can twist things easily. The maximum torque is when r and F are at 90º.

2. The direction of the torque is along the axis of rotation, perpendicular to the plane of rotation, as defined by a right hand rule: extend fingers along r from center outward, allow fingers to curl in direction of F applied, and your thumb indicates the direction of the torque.

4.  boy -  girl = 0 r x F - r x F = 0 1m x 800N - x x 350N = 0 solve x: x = 800/350 = 2.16 m

5. What if all forces are not at right angles wrt the moment arm ? 1.Draw an extended FBD 2. 2.  T =0 3. Use T= r x F = r F sin for each torque First lets solve the case where the man is not there and the boom has a mass of 500 kg.

6. hinge boom

7. Now solve for tension in the cable when a 80 kg man stands 2 meters from the wall.

12. Spinning wheel, CM not translating (Vcm=0) Spinning wheel, CM translating (Vcm >0) {rolling} Calculate v at all the points if R = 1m and  = 1 rad/sec Vp’= Vcm= Vp= +1m/s 0 -1m/s Calculate v at all the points if R = 1m and  = 1 rad/sec Vp’= Vcm= Vp= +2 m/s +1 m/s 0 m/s

13. Is this disk rolling or spinning in place?

15. Angular momentum L= r x p = r x mv