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3.4A-Fundamental Counting Principle The number of ways 2 events can occur in sequence (1 after the other) is m x n and it can be extended for more events.

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Presentation on theme: "3.4A-Fundamental Counting Principle The number of ways 2 events can occur in sequence (1 after the other) is m x n and it can be extended for more events."— Presentation transcript:

1 3.4A-Fundamental Counting Principle The number of ways 2 events can occur in sequence (1 after the other) is m x n and it can be extended for more events. Example: You buy a car. The dealer carries: 3 brands (Ford, GM, and Chrysler) in 2 sizes (small & medium)and in 4 colors(white, red, black & green). How many options do you have? Make a tree diagram. If the dealer added Toyota, Large, Tan and Gray to the previous options, how many are there?

2 3.4A-Fundamental Counting Principle The number of ways 2 events can occur in sequence (1 after the other) is m x n and it can be extended for more events. Example: You buy a car. The dealer carries: 3 brands (Ford, GM, and Chrysler) in 2 sizes (small & medium)and in 4 colors(white, red, black & green). How many options do you have? Make a tree diagram. 3x2x4 = 24 options Ford GMChrysler S M S M S M W R B G W R B G W R B G

3 3.4A-Fundamental Counting Principle The number of ways 2 events can occur in sequence (1 after the other) is m x n and it can be extended for more events. Example: You buy a car. The dealer carries: 3 brands (Ford, GM, and Chrysler) in 2 sizes (small & medium)and in 4 colors(white, red, black & green). How many options do you have? Make a tree diagram. If the dealer added Toyota, Large, Tan and Gray to the previous options, how many are there? 4x3x6 = 72

4 More examples A car access code has 4 digits (0-9). How many codes are possible if: – A) each can be used just once (NO REPEATS!) – B) each digit CAN REPEAT

5 More examples A car access code has 4 digits (0-9). How many codes are possible if: – A) each can be used just once (NO REPEATS!) 10x9x8x7=5040 – B) each digit CAN REPEAT

6 More examples A car access code has 4 digits (0-9). How many codes are possible if: – A) each can be used just once (NO REPEATS!) 10x9x8x7=5040 – B) each digit CAN REPEAT 10x10x10x10 = 10,000

7 More examples How many license plates can be made if each plate has 6 letters (there are 26 possible) and: – A) repeated letters are allowed – B) No repeats of letters

8 More examples How many license plates can be made if each plate has 6 letters (there are 26 possible) and: – A) repeated letters are allowed 26x26x26x26x26x26 =308,915,776 – B) No repeats of letters

9 More examples How many license plates can be made if each plate has 6 letters (there are 26 possible) and: – A) repeated letters are allowed 26x26x26x26x26x26 =308,915,776 – B) No repeats of letters 26x25x24x23x22x21 = 165,765,600

10 More examples How many different ways can you flip a coin, roll a 6-sided die and answer a true/false question? Draw a tree diagram for it.

11 More examples How many different ways can you flip a coin, roll a 6-sided die and answer a true/false question? 2x6x2 = 24 Draw a tree diagram for it.

12 More examples How many different ways can you flip a coin, roll a 6-sided die and answer a true/false question? 2x6x2= 24 Draw a tree diagram for it. HT 1 2 3 4 5 6 1 2 3 4 5 6 T F T F T F T F T F T F T F T F T F T F T F T F


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