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Solving Quadratic Equations Cont’d.. To Solve A Quadratic Equation When b = 0… Use the same procedures you used to solve an equation to get the “x” isolated.

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Presentation on theme: "Solving Quadratic Equations Cont’d.. To Solve A Quadratic Equation When b = 0… Use the same procedures you used to solve an equation to get the “x” isolated."— Presentation transcript:

1 Solving Quadratic Equations Cont’d.

2 To Solve A Quadratic Equation When b = 0… Use the same procedures you used to solve an equation to get the “x” isolated (by itself). Instead of having an “x” left, you have an “x²”. When the “x²” is isolated, find the square root of both sides (be sure to give both the principal and the negative roots!).

3 Example 1 Solve:2x² - 18 = 0 Add 18 to both sides2x² = 18 Divide both sides by 2x² = 9 Find the square root of both sides x = ± 3

4 Example 2 Solve:2x² + 72 = 0 Subtract 72 from both sides 2x² = -72 Divide both sides by 2x² = -36 Find the square root of both sides— oops!! You can’t find the square root of a negative number (-36) so there is NO SOLUTION!

5 Try these… 4x 2 + 1 = 17 Find the radius of a circle whose area is 125 in 2. 81x 2 - 49 = 0 3x 2 – 85 = 2x 2 – 36 4x 2 + 72 = 2x 2 - 28

6 The Quadratic Formula

7 The Discriminant This is the part of the equation under the radical sign. (b 2 – 4ac) When that is positive, there will be two answers. When that is negative, there will be no real solution. When that is zero, there will be one answer.

8 Find the number of solutions: 2x 2 + 4x + 3 = 0 a = 2; b = 4; c = 3 b 2 – 4ac (4) 2 – (4)(2)(3) 16 – 24= -8 The answer is negative, so there are no real solutions.

9 Find the number of solutions: 2x 2 – 11x + 6 = 0 a = 2; b = -11; c = 6 b 2 – 4ac (-11) 2 – (4)(2)(6) 121 – 48= 73 The answer is positive, so there are two real solutions.

10 Find the number of solutions: 2x 2 + 12x = -18 2x 2 + 12x + 18 = 0 a = 2; b = 12; c = 18 b 2 – 4ac (12) 2 – (4)(2)(18) 144 – 1444= 0 The answer is zero, so there is one real solution.

11 Try these… 3x + 2x 2 + 6 = 0 3x 2 = 13x – 4 9x 2 + 16 = -24x

12 Quadratic Formula

13 6x 2 + 7x – 5 = 0 a = 6, b = 7, c = -5

14 5x 2 – 4x = 33 -33 -33 5x 2 – 4x – 33 = 0 a = 5, b = -4, c = -33

15 6x 2 – 150 = 0 Since b = 0, I would use the square root method. Add 130 to both sides 6x 2 = 150 Divide both sides by 6 x 2 = 25 Find the square root of both sides and round to the nearest hundredth. x = 5, and –5

16 Try these… x 2 + x – 12 = 0 2x 2 + x – 7 = 0


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