1. Warm Up Evaluate and simplify the ratios when x = 2 and y = –2. ANSWER 1. x 5 – y + 3 1 3 – 3 4 – x 6 2. 1 y – – 3. A cross-country skier traveled 14 miles in 3.5 hours. Use the formula d = rt where d is distance, r is rate, and t is time, to find the average rate of speed. ANSWER 4 mi/h

2. 1.5 Find Slope and Rate of Change

3. EXAMPLE 1 Find a positive slope Let (x 1, y 1 ) = (–4, 2) = (x 2, y 2 ) = (2, 6). m = y 2 – y 1 x 2 – x 1 Find the slope of the line shown.

4. EXAMPLE 2 Write an equation from a graph GUIDED PRACTICE for Example 1 Find the slope of the line that passes through the points. 1. (5, 2) and (4, –1) 2. (, 5) and (, –3) 9 2 1 2

5. Horizontal and Vertical lines The slope of a horizontal line is ________________. The slope of a vertical line is ________________.

6. EXAMPLE 2 Write an equation from a graph GUIDED PRACTICE for Examples 2, 3 and 4 Find the slope of the line that passes through the points. 4. (5, 2) and (5, – 2) 5. (0, 4) and (– 3, 4)

7. EXAMPLE 7 Example: Find the value of y so that the line passing through the two points has the given slope. (–3, y), (–9, –2); m = 4 / 3

8. EXAMPLE 6 Use a graph to find and compare rates of change COMMUNITY THEATER A community theater performed a play each Saturday evening for 10 consecutive weeks. The graph shows the attendance for the performances in weeks 1, 4, 6, and 10. Describe the rates of change in attendance with respect to time.

9. SOLUTION EXAMPLE 6 Use a graph to find and compare rates of change Find the rates of change using the slope formula. Weeks 1–4: 232 – 124 4 – 1 = 108 3 = 36 people per week Weeks 4–6: 204 – 232 6 – 4 = – 28 2 = – 14 people per week Weeks 6–10: 72 – 204 10 – 6 = – 132 4 = – 33 people per week ANSWER Attendance increased during the early weeks of performing the play. Then attendance decreased, slowly at first, then more rapidly.

10. EXAMPLE 7 Interpret a graph COMMUTING TO SCHOOL A student commutes from home to school by walking and by riding a bus. Describe the student’s commute in words.

11. EXAMPLE 7 Interpret a graph The first segment of the graph is not very steep, so the student is not traveling very far with respect to time. The student must be walking. The second segment has a zero slope, so the student must not be moving. He or she is waiting for the bus. The last segment is steep, so the student is traveling far with respect to time. The student must be riding the bus. SOLUTION