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Unit 3 Review Scavenger Hunt

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The function y = 187900 (1.025) x represents the value of a home x years after purchase. What is the rate of appreciation of the home? 1.025% (Go to Station A) 25% (Go to Station B) 2.5% (Go to Station F) 187900% (Go to Station C) Station A

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Station F The function y = 290,000 (0.92) x represents the value of an old home that has been abandoned by its owners x years ago. Find the decay rate of the old home. 92% (Go to Station V) 8% (Go to Station H).92% (Go to Station C).8% (Go to Station R)

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Station H Solve the following: 3(10) x + 4 + 3 = 15 x= -3.4 (Go to Station R) x = 4 (Go to Station E) X = -5 (Go to station F) x = 3.4 (Go to Station Y)

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Station R Find the inverse of the following set of points: f(x) = {(4, -7), (9, 8), (1, 7), (6, 2)} f -1 (x) = { (-7,4), (8, 9), (7, 1), (2, 6)} (Go to Station O) f -1 (x) = { (-4, 7), (-9, -8), (-1, -7), (-6, -2)} (Go to Station T) f -1 (x) = { (7,4), (-8, -9), (7, 1), (2, 6)} (Go to Station X) f -1 (x) = { (-4,7), (8, 9), (7, 1), (2, 6)} (Go to Station E)

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Station O Evaluate the following logarithm: log 10 2.9 = ? 2 (Go to Station A) -2.9 (Go to Station H) Not Possible (Go to Station J) 2.9 (Go to Station W)

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Station W Find the inverse of the following function f(x) = f -1 (x) = -1/3x – 6 (Go to Station O) f -1 (x) = 3x-18 (Go to Station T) f -1 (x) = 3x – 6 (Go to Station H) f -1 (x) = -3x + 6 (Go to Station A)

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Station T Simplify the following expression: 8s 2 (Go to Station R) 8s 4 (Go to Station U) 64s 29 (Go to Station S) 8s (Go to Station B)

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Station U Use the exponent rules to solve for x in the following: x = 3 (Go to Station W) x = 2/3 (Go to Station T) x = 16 (Go to Station B) x = 4 (Go to Station O) (3 2x )(3 16 ) = 3 48

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Station B A popular antique is gaining value because it is so hard to find. In 1985 its value was $125, and in 2000 its value was $1925.90. Write the exponential function to model the value of this antique. y = 125 (1.2) x (Go to Station M) y = 1925.90 (1.2) x (Go to Station F) y = 125 (.8) x (Go to Station U) y = 125 (10) x (Go to Station V)

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Station M For the function f(x) = (0.75) x – 1, evaluate f(2) f(2) =.4375 (Go to Station T) f(2) = -.4375 (Go to Station A) f(2) =.5625 (Go to Station F) f(2) = -.5625 (Go to Station R)

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