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MAT 2720 Discrete Mathematics Section 8.7 Planar Graphs

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Presentation on theme: "MAT 2720 Discrete Mathematics Section 8.7 Planar Graphs"— Presentation transcript:

1 MAT 2720 Discrete Mathematics Section 8.7 Planar Graphs http://myhome.spu.edu/lauw

2 Goals Define Planar Graphs The conditions for a graph to be planar Series Reductions Homeomorphic Graphs

3 Example 1 The following are 2 ways of drawing the same graph, K 4.

4 Definition A graph is planar if it can be drawn in the plane without its edges crossing.

5 Definition A graph is planar if it can be drawn in the plane without its edges crossing. K 4 is planar K 5 is NOT planar K 3,3 is NOT planar

6 Faces of a Planar Graph

7 Euler’s Formula for Graphs If G is a connected, planar graph with e edges, v vertices, and f faces, then f=e-v+2

8 Euler’s Formula for Graphs If G is a connected, planar graph with e edges, v vertices, and f faces, then f=e-v+2

9 Example 2 K 3,3 is NOT planar

10 Example 2 Suppose K 3,3 is planar 1. Every cycle has at least 4 edges.

11 Example 2 Suppose K 3,3 is planar 1. Every cycle has at least 4 edges. 2.The no. of edges that bound faces is at least 4f (with some edges counted twice). f=e-v+2

12 Observations A graph contains K 3,3 or K 5 as a subgraph is NOT planar.

13 Observations A graph contains a graph “somewhat” similar to K 3,3 or K 5 as a subgraph is NOT planar.

14 Definitions (simplified) Edges in Series Series Reduction

15 Homeomorphic Two graphs are homeomorphic if they can be reduced to isomorphic graphs by a sequence of series reduction.

16 Example 3 The following graphs are homeomorphic.

17 Finally…Kuratowski’s Theorem A graph is planar iff it does not contain a subgraph homeomorphic to K 3,3 or K 5.

18 Example 3 Show that the following graph is not planar.

19 Example 3 Key: Locate the subgraph homeomorphic to K 3,3 or K 5

20 Example 3: Formal Solutions Eliminating edges (a,b), (f,e), and (g,h) eliminating vertices g and h

21 Example 3: Formal Solutions Eliminating edges (a,b), (f,e), and (g,h) eliminating vertices g and h Since the graph contains a subgraph homeomorphic to K 3,3, it is not planar


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