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6.5 and 6.6 Solving Absolute Value Equations & Inequalities Page 322 Textbook Indicators: PFA 7,8 and 9.

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Presentation on theme: "6.5 and 6.6 Solving Absolute Value Equations & Inequalities Page 322 Textbook Indicators: PFA 7,8 and 9."— Presentation transcript:

1 6.5 and 6.6 Solving Absolute Value Equations & Inequalities Page 322 Textbook Indicators: PFA 7,8 and 9

2 Absolute Value (of x) Symbol lxl The distance x is from 0 on the number line. Always positive Ex: l-3l=3 -4 -3 -2 -1 0 1 2

3 Let’s look at x = 5 What are the possible values of x? x = 5 or x = -5

4 To solve an absolute value equation: ax+b = c, where c>0 To solve, set up 2 new equations, then solve each equation. ax+b = c or ax+b = -c ** make sure the absolute value is by itself before you split to solve.

5 Example 1: Solve 6x-3 = 15 6x-3 = 15 or 6x-3 = -15 6x = 18 or 6x = -12 x = 3 or x = -2 * Plug in answers to check your solutions!

6 Example 2: Solve 2x + 7 -3 = 8 Get the absolute value part by itself first! 2x+7 = 11 Now split into 2 parts. 2x+7 = 11 or 2x+7 = -11 2x = 4 or 2x = -18 x = 2 or x = -9 Check the solutions.

7 Let’s look at: x < 5 What are the possible values of x? Remember this is an AND statement. Let’s look at integer examples: x = …, 2, 3, 4 or x = -4, -3, -2, …

8 Let’s look at: x > 5 What are the possible values of x? Remember this is an OR statement. Let’s look at integer examples: x = 6, 7, 8, … or x =..., -8, -7, -6

9 Solving Absolute Value Inequalities 1.ax+b 0 Becomes an “and” problem Changes to: –c<ax+b<c 2.ax+b > c, where c>0 Becomes an “or” problem Changes to: ax+b>c or ax+b<-c

10 Example 3: Solve & graph. Becomes an “and” problem The absolute value of 4x – 9 < 21 4x – 9 -21 4x -12 x -3 -3 7 8

11 Example 4: Solve & graph. Becomes an “or” problem The absolute value of 3x – 2 > 8 3x - 2 > 8or3x – 2 < -8 3x > 103x < -6 x > 10/3 x < -2 -2 3 4

12 Warning!!! Do not forget to reverse the inequality sign when you multiply or divide by a negative quantity!!!

13 Assignment

14 Ex: Solve & graph. Becomes an “and” problem -3 7 8

15 Solve & graph. Get absolute value by itself first. Becomes an “or” problem -2 3 4


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