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© 2007 Pearson Education South Asia Pte Ltd Teaching Slides – Free-Body Diagrams Chapter 5: Equilibrium of a Rigid Body.

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Presentation on theme: "© 2007 Pearson Education South Asia Pte Ltd Teaching Slides – Free-Body Diagrams Chapter 5: Equilibrium of a Rigid Body."— Presentation transcript:

1 © 2007 Pearson Education South Asia Pte Ltd Teaching Slides – Free-Body Diagrams Chapter 5: Equilibrium of a Rigid Body

2 © 2007 Pearson Education South Asia Pte Ltd Teaching Slides – Free-Body Diagrams Example 5.5 The free-body diagram of each object is drawn. Carefully study each solution and identify what each loading represents. (a) (b) (c) (d)

3 © 2007 Pearson Education South Asia Pte Ltd Teaching Slides – Free-Body Diagrams Example 5.5 (a) 200 N y x 3 4 5 ByBy BxBx A B 30°

4 © 2007 Pearson Education South Asia Pte Ltd Teaching Slides – Free-Body Diagrams Example 5.5 (b) y x AxAx AyAy A B 30° 500 Nm T

5 © 2007 Pearson Education South Asia Pte Ltd Teaching Slides – Free-Body Diagrams Example 5.5 (c) y x AxAx ByBy A B 30° 400 Nm MAMA

6 © 2007 Pearson Education South Asia Pte Ltd Teaching Slides – Free-Body Diagrams Example 5.5 (d) y x ByBy A B AxAx AyAy 5 kN 4 kN Note: Internal forces of one member on another are equal but opposite collinear forces which are not to be included here since they cancel out.

7 © 2007 Pearson Education South Asia Pte Ltd Teaching Slides – Free-Body Diagrams Example 5.12 The uniform truck ramp has a weight of 1600N (≈ 160kg) and is pinned to the body of the truck at each end and held in position by two side cables. Determine the tension in the cables.

8 © 2007 Pearson Education South Asia Pte Ltd Teaching Slides – Free-Body Diagrams Example 5.12 T AyAy A B 20° 10° AxAx y x 1600 N G 20° C T d Since there are two cables supporting the ramp, T’ = T/2 = 2992.5N

9 © 2007 Pearson Education South Asia Pte Ltd Teaching Slides – Free-Body Diagrams Example 5.13 The lever ABC is pin-supported at A and connected to a short link BD. If the weight of the members are negligible, determine the force of the pin on the lever at A.

10 © 2007 Pearson Education South Asia Pte Ltd Teaching Slides – Free-Body Diagrams Example 5.13 B D A C F F 45° 400 N 45°θ O FAFA

11 © 2007 Pearson Education South Asia Pte Ltd Teaching Slides – Free-Body Diagrams Example 5.14 Several examples of objects along with their associated free-body diagrams are shown. In all cases, the x, y and z axes are established and the unknown reaction components are indicated in the positive sense. The weight of the objects is neglected. (a) (b)(c)(d)

12 © 2007 Pearson Education South Asia Pte Ltd Teaching Slides – Free-Body Diagrams Example 5.14(a) y x zz B A C AyAy AxAx BxBx ByBy CxCx CyCy 500 N

13 © 2007 Pearson Education South Asia Pte Ltd Teaching Slides – Free-Body Diagrams Example 5.14(b) y x zz B A 300 N T AxAx AyAy AzAz M Az M Ax 200Nm

14 © 2007 Pearson Education South Asia Pte Ltd Teaching Slides – Free-Body Diagrams Example 5.14(c) y x zz 400 N BxBx CxCx CyCy CzCz AzAz AxAx

15 © 2007 Pearson Education South Asia Pte Ltd Teaching Slides – Free-Body Diagrams Example 5.14(d) y x zz B A 6 kN T AxAx AyAy AzAz M Az 4 kN M Ay

16 © 2007 Pearson Education South Asia Pte Ltd Teaching Slides – Free-Body Diagrams Example 5.19 The bent rod is supported at A by a journal bearing, at D by a ball and socket joint, and at B by means of cable BC. Using only one equilibrium equation, obtain a direct solution for the tension in cable BC. The bearing at A is capable of exerting force components only in the z and y directions since it is properly aligned.

17 © 2007 Pearson Education South Asia Pte Ltd Teaching Slides – Free-Body Diagrams Example 5.19 y x zz DzDz DyDy AyAy AzAz DxDx W = 981 N B A D E u


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