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Good Morning! Please get the e-Instruction Remote with your assigned Calculator Number on it, and have a seat… Then answer this question by aiming the.

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Presentation on theme: "Good Morning! Please get the e-Instruction Remote with your assigned Calculator Number on it, and have a seat… Then answer this question by aiming the."— Presentation transcript:

1 Good Morning! Please get the e-Instruction Remote with your assigned Calculator Number on it, and have a seat… Then answer this question by aiming the remote at the white receiver by my computer and pressing your answer choice!

2 Warm Up Write each function in standard form. Evaluate b 2 – 4ac for the given values of the valuables. 1. f(x) = (x – 4) 2 + 3 2. g(x) = 2(x + 6) 2 – 11 f(x) = x 2 – 8x + 19 g(x) = 2x 2 + 24x + 61 4. a = 1, b = 3, c = –3 3. a = 2, b = 7, c = 5 9 21

3 Solve quadratic equations using the Quadratic Formula. Objectives

4 You have learned several methods for solving quadratic equations: graphing, making tables, factoring, using square roots, and completing the square. Another method is to use the Quadratic Formula, which allows you to solve a quadratic equation in standard form. By completing the square on the standard form of a quadratic equation, you can determine the Quadratic Formula.

5 Make sure the equation is in standard form before you evaluate the discriminant, b 2 – 4ac. Caution!

6 Find the type and number of solutions for the equation. Example 3A: Analyzing Quadratic Equations by Using the Discriminant x 2 + 36 = 12x x 2 – 12x + 36 = 0 b 2 – 4ac (–12) 2 – 4(1)(36) 144 – 144 = 0 b 2 – 4ac = 0 The equation has one distinct real solution.

7 Find the type and number of solutions for the equation. Example 3B: Analyzing Quadratic Equations by Using the Discriminant x 2 + 40 = 12x x 2 – 12x + 40 = 0 b 2 – 4ac (–12) 2 – 4(1)(40) 144 – 160 = –16 b 2 –4ac < 0 The equation has two distinct nonreal complex solutions.

8 Find the type and number of solutions for the equation. Example 3C: Analyzing Quadratic Equations by Using the Discriminant x 2 + 30 = 12x x 2 – 12x + 30 = 0 b 2 – 4ac (–12) 2 – 4(1)(30) 144 – 120 = 24 b 2 – 4ac > 0 The equation has two distinct real solutions.

9 The discriminant is part of the Quadratic Formula that you can use to determine the number of real roots of a quadratic equation.

10 You can use the Quadratic Formula to solve any quadratic equation that is written in standard form, including equations with real solutions or complex solutions.

11 Quadratic Song Video!

12 Khan Academy Video!

13 Find the zeros of f(x)= 2x 2 – 16x + 27 using the Quadratic Formula. Example 1: Quadratic Functions with Real Zeros Set f(x) = 0. Write the Quadratic Formula. Substitute 2 for a, –16 for b, and 27 for c. Simplify. Write in simplest form. 2x 2 – 16x + 27 = 0

14 Find the zeros of f(x) = x 2 + 3x – 7 using the Quadratic Formula. Set f(x) = 0. Write the Quadratic Formula. Substitute 1 for a, 3 for b, and –7 for c. Simplify. Write in simplest form. Check It Out! Example 1a x 2 + 3x – 7 = 0

15 Find the zeros of f(x)= x 2 – 8x + 10 using the Quadratic Formula. Set f(x) = 0. Write the Quadratic Formula. Substitute 1 for a, –8 for b, and 10 for c. Simplify. Write in simplest form. Check It Out! Example 1b x 2 – 8x + 10 = 0

16 Find the zeros of f(x) = 4x 2 + 3x + 2 using the Quadratic Formula. Example 2: Quadratic Functions with Complex Zeros Set f(x) = 0. Write the Quadratic Formula. Substitute 4 for a, 3 for b, and 2 for c. Simplify. Write in terms of i. f(x)= 4x 2 + 3x + 2

17 Find the zeros of g(x) = 3x 2 – x + 8 using the Quadratic Formula. Set f(x) = 0 Write the Quadratic Formula. Substitute 3 for a, –1 for b, and 8 for c. Simplify. Write in terms of i. Check It Out! Example 2

18 The graph shows related functions. Notice that the number of real solutions for the equation can be changed by changing the value of the constant c.

19 Properties of Solving Quadratic Equations

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21 No matter which method you use to solve a quadratic equation, you should get the same answer. Helpful Hint

22 Lesson Quiz: Part I Find the zeros of each function by using the Quadratic Formula. 1. f(x) = 3x 2 – 6x – 5 2. g(x) = 2x 2 – 6x + 5 Find the type and member of solutions for each equation. 3. x 2 – 14x + 504. x 2 – 14x + 48 2 distinct nonreal complex 2 distinct real

23 Homework! Holt Chapter 5 Section 6 Page 361 # 19-39 odd, 45-53 odd

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