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Transformation Interest problems Half life

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Presentation on theme: "Transformation Interest problems Half life"— Presentation transcript:

1 Transformation Interest problems Half life
3.1 Exponential Function Transformation Interest problems Half life

2 Exponential Function f(x) = ax a > 0 and a ≠ 1
x is any real number. Notice 20 = 1 Any number to the zero power (except 0) equals 1

3 What if there is x is a negative number
We would have a decreasing exponential function

4 What is the horizontal asymptote?
We would have a decreasing exponential function

5 Transformations (shifts happen)
y = 4x y = 4x + 3

6 Now a little to the right
y = 4x y = 4(x – 3)

7 Reflect across the y axis
y = 4x y = 4-x

8 Lets use a different base
What do you see?

9 How about the base e e ≈ 2.71828 ……… it is transcendental. e ≈
Just another base that most natural event follow

10 Base 10 is also common, that it is on your calculators

11 Continuous Compounding Interest uses e
Now for my favorite equation. Pert P is for principle r is for Rate t is for Time $4000 at 8% interest for 10 years at continuous compounding interest. 4000e(.08)(10) =

12 Continuous Compounding Interest uses e
Now for my favorite equation. Pert P is for principle r is for Rate t is for Time $4000 at 8% interest for 10 years at continuous compounding interest. 4000e(.08)(10) = $

13 Compounding a number of times per year equation
Amount = N is the number of times per year Quarterly is 4 Semi Annual is 2 Monthly is 12

14 Decay function In a decay function a (the base) is 0 < a< 1
In other words a fraction The most famous is half life, where a is ½. h is half life P initial amount A is remaining amount

15 Homework Page 206 – 208 # 2, 7, 13, 21, 33, 43, 47, 51, 54, 57, 61, 67

16 Homework Page 206 – 208 # 4, 10, 17, 27, 37, 45, 49, 53, 55, 58, 62, 78


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