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Electrochemistry - Section 1 Voltaic Cells

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Presentation on theme: "Electrochemistry - Section 1 Voltaic Cells"— Presentation transcript:

1 Electrochemistry - Section 1 Voltaic Cells
Chemistry - Chapter 21 Electrochemistry - Section 1 Voltaic Cells

2 Half-Reactions Two terms that you must know: Oxidation Reduction

3 Half-Reactions Two terms that you must know: Oxidation
The process of loosing electrons Example: Zn  Zn e-

4 Half-Reactions Two terms that you must know: Reduction
The process of gaining electrons Example: Cu e-  Cu

5 Half-Reactions Two terms that you must know:
Oxidation and reduction occur in pairs in all chemical reactions Remember this: OIL RIG (Oxidation Is Loosing, Reduction Is Gaining)

6 Setting up the Redox Reaction
Keeping the Half-Reactions separate is important. Creating a path for the flow of electrons is a must! (done with a wire and salt bridge)

7 Electrochemical Cells
The Salt Bridge allows the charge to balance.

8 Electrochemical Cells
Note that the metal strip is in contact with a solution that is similar. i.e. Zinc in a solution of zinc nitrate and copper in solution of copper II nitrate.

9 Half-Reactions and Cells
Each cell has a half-reaction taking place within. The oxidation takes place at the anode The reduction takes place at the cathode The reaction proceeds in such a way as to end with a more stable system: the electrical potential of the cell

10 Calculating Cell Potential
Reduction potential is the tendency of a substance to gain electrons. Measured in volts Must be determined in connection with another substance Determine the difference in potential of the two cells Standard Hydrogen electrode is used to compare all cells This cell is defined as having a potential of 0.0 V

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12 Calculating Cell Potential
One like this is found on page 667 in your text

13 Calculating Cell Potential
The value of the cell potential is calculated by subtraction of the standard reduction potential of the oxidation half-reaction from the standard reduction potential of the reduction half reaction. Eocell Eoreduction Eooxidation = -

14 Calculating Cell Potential
Using cell notation we see this: Cu(s)ᅵCu2+(aq)║Zn2+(aq)ᅵZn(s) Cathode half-cell Anode half-cell Salt Bridge

15 Calculating Cell Potential
Eocell = EoCu2+ǀCu - EoZnǀZn2+ For this reaction, then, we have the following: Eocell = V - ( V) = V


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