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F.V. and S.V.of an object are given. Draw it’s isometric view.

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Presentation on theme: "F.V. and S.V.of an object are given. Draw it’s isometric view."— Presentation transcript:

1 F.V. and S.V.of an object are given. Draw it’s isometric view.
40 20 30 SQUARE 50 60 30 10 F.V. L.S.V. O O O

2 Draw the isometric view from the two views given
FV TV

3

4 B 2 2 C 4 A B 4 3 A 3 1 C D D 1 DRAW ISOMETRIC VIEW OF A
CIRCLE IF IT IS A TV OR FV. FIRST ENCLOSE IT IN A SQUARE. DRAW A RHOMBUS REPRESENTING THE SQUARE IN ISOMETRIC FOUR CENTER METHOD JOIN OBTUSE ANGLE CORNERS TO THE MID POINT OF THE OPPOSITE SIDES 4 CENTERS ARE 1, 2, 3, AND 4 AS SHOWN WITH 1 AND 2 AS CENTERS, DRAW ARCS AB AND DC WITH 3 AND 4 AS CENTERS, DRAW ARCS AD AND BC 2 A B D C 2 4 A B D C 3 4 3 1 1

5 Isometric view of circle – Method of points
8 k k d a d 8 j j e 4 1 l a 4 1 e 7 5 7 i 2 3 f i 5 3 2 c b g h c 6 h f 6 Draw diagonals of the enclosing square Mark points 1, 2, 3, 4 on the circle and measure their distances from the edges of the rectangle Mark corresponding distances in the isometric view to obtain the points 1,2, 3, 4 g b 4 points can be obtained as the end points of the diameters drawn parallel to the axes

6 DRAW ISOMETRIC VIEW OF THE FIGURE
SHOWN WITH DIMENTIONS (ON RIGHT SIDE) CONSIDERING IT FIRST AS horizontal AND THEN vertical 25 R 100 MM 50 MM IF FRONT VIEW IF TOP VIEW

7 CYLINDER WITH AXIS VERTICAL
Draw a cylinder of height 50 mm and diameter 30 mm i) With axis horizontal, ii) With axis vertical CYLINDER WITH AXIS VERTICAL CYLINDER WITH AXIS HORIZONTAL

8 ISOMETRIC VIEW OF A FRUSTOM OF CONE STANDING ON H. P
ISOMETRIC VIEW OF A FRUSTOM OF CONE STANDING ON H.P. ON IT’S LARGER BASE. f40 f20 60 X Y FV TV

9 Construction Final

10 FV TV F.V. & T.V. of an object are given. Draw it’s isometric view. O
40 10 50 80 30 f 25 FV TV O O

11 Isometric view of a sphere
All orthographic views of a sphere are a circle with radius = radius of the sphere When drawing the isometric view from the 3 orthographic views, we therefore get 3 ellipses as shown The isometric view is therefore drawn as a circle enclosing the 3 ellipses The circle radius is approximately 1.22 times the actual sphere radius Therefore when we draw an isometric view which includes a spherical feature, we either draw the sphereical feature with 1.22 x radius and rest normal size OR We draw the circle normal size and decrease the rest of the figure (0.82 times)

12 Sphere resting on a square platform
The following figures show the orthographic and isometric views of a sphere resting on a square platform. The isometric view of the sphere is shown. Spherical scale, is used to obtain the radius of the sphere in isometric view. The square platform in the isometric view is drawn using the original dimensions. Note the point of contact P of the sphere with the platform which is the point of intersection of the diagonals of the square. P1 Sphere is touching the platform at P and not P1

13 Sphere with normal radius
The rectangular slab has a shortened length of side. Sphere radius Other dimensions 1.22 times Normal 0.82 times

14 NOTE In this course: No hidden lines are to be drawn in an isometric view No dimensioning is to be done on an isometric view Orthographic views are convenient for marking dimensions and viewing all features of an object Isometric views are for getting an idea of how the object will look in 3-D

15 F.V. and S.V.of an object are given. Draw it’s isometric view.
20 15 30 60 40 100 50 HEX PART O O

16

17 PENTAGONALL PRISM WITH AXIS HORIZONTAL
ISOMETRIC VIEW OF PENTAGONALL PRISM WITH AXIS HORIZONTAL 1 2 3 4 A B C D E 1 2 3 4 A B C D E H L

18 50 50 PROBLEM: A SQUARE PYRAMID OF 30 MM BASE SIDES AND
50 MM LONG AXIS, IS CENTRALLY PLACED ON THE TOP OF A CUBE OF 50 MM LONG EDGES.DRAW ISOMETRIC VIEW OF THE PAIR. 50 30 50

19 ( with flat face // to H.P.)
HALF CYLINDER STANDING ON H.P. ( ON IT’S SEMICIRCULAR BASE) HALF CYLINDER LYING ON H.P. ( with flat face // to H.P.)

20 PROJECTIONS OF FRUSTOM OF PENTAGONAL PYRAMID ARE GIVEN.
DRAW IT’S ISOMETRIC VIEW. ISOMETRIC VIEW OF FRUSTOM OF PENTAGONAL PYRAMID 60 y A B C D E 40 20 60 x FV TV SOLUTION STEPS: FIRST DRAW ISOMETRIC OF IT’S BASE. THEN DRAWSAME SHAPE AS TOP, 60 MM ABOVE THE BASE PENTAGON CENTER. THEN REDUCE THE TOP TO 20 MM SIDES AND JOIN WITH THE PROPER BASE CORNERS. 20 1 2 3 4 40


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