Presentation is loading. Please wait.

Presentation is loading. Please wait.

Isotopes and Ions. Fill in the following table: Symbol Atomic Mass Atomic Number # of protons # of neutrons # of electrons Na Na Ne Ne Hg Hg Zn Zn Al.

Similar presentations


Presentation on theme: "Isotopes and Ions. Fill in the following table: Symbol Atomic Mass Atomic Number # of protons # of neutrons # of electrons Na Na Ne Ne Hg Hg Zn Zn Al."— Presentation transcript:

1 Isotopes and Ions

2 Fill in the following table: Symbol Atomic Mass Atomic Number # of protons # of neutrons # of electrons Na Na Ne Ne Hg Hg Zn Zn Al Al 23 11 20 10 201 80 65 30 27 13

3 Fill in the following table: Symbol Atomic Mass Atomic Number # of protons # of neutrons # of electrons 1275354 Cd Cd112 385036 X7554 X10342 2+ 2- 3+

4 What is an Ion? An atom that is positively or negatively charged An atom that is positively or negatively charged An atom that is positively charged has ____ electrons than the number of protons An atom that is positively charged has ____ electrons than the number of protons An atom that is negatively charged has ____ electrons than the number of protons An atom that is negatively charged has ____ electrons than the number of protons

5 What is an Isotope? Atoms of the same element that contain different numbers of neutrons Atoms of the same element that contain different numbers of neutrons Example: Example:  Nitrogen has two isotopes: Nitrogen-14 ( 14 N) and Nitrogen-15 ( 15 N)  Nitrogen 14 has _________ neutrons  Nitrogen 15 has _________ neutrons

6 Determining the average atomic mass The average atomic mass (  of an element depends on the proportions of the isotopes. Sample 1: 10 B = 18.8% 11 B = 81.2% Average = (% 10 B)(mass of 10 B) + (% 11 B)(mass of 11 B) = (0.188)(10) + (0.812)(11) = 1.88 + 8.982 = 10.812  The average atomic mass for Boron is 10.812 

7 Determine the % of each isotope Given the average atomic mass and the isotopes present in the mixture, the % of each isotope present can be calculated. Example: Calculate the % of each isotope present in the mixture of 107 Ag and 109 Ag that has an average mass of 107.9  Let x represent 107 Ag and (1-x) represent 109 Ag 107 x + 109 (1 – x) = 107.9 107 x + 109 – 109 x = 107.9 2 x = 1.1 x = 0.55 1 – x = 0.45 Therefore 107 Ag = 55% and 109 Ag = 45%


Download ppt "Isotopes and Ions. Fill in the following table: Symbol Atomic Mass Atomic Number # of protons # of neutrons # of electrons Na Na Ne Ne Hg Hg Zn Zn Al."

Similar presentations


Ads by Google