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Picture of an enzymatic reaction. Velocity =  P/  t or -  S/  t Product Time.

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Presentation on theme: "Picture of an enzymatic reaction. Velocity =  P/  t or -  S/  t Product Time."— Presentation transcript:

1 Picture of an enzymatic reaction

2 Velocity =  P/  t or -  S/  t Product Time

3 Rate constants are defined for reactions V =  P/  t = -  S/  t = k 1 [S] k 1 is called the rate constant and has units of s -1 If k 1 is small, the reaction rate is slow, if large the reaction is fast A k of 0.03 s-1 indicates that 3% of the available S will be converted to P in 1 sec

4 Relationship between V and [S]

5 Molecular parameters from reaction rates Assume the conversion of ES to E + P is non-reversible, then the rate of product formation or reaction velocity is dependent solely on [ES] and k 2 E + S ES E + P k1k1 k-1k-1 k2k2 v = d[P]/dt = k 2 [ES] (1) If we could measure v and [ES] then we could determine k 2, however [ES] is not usually measurable. We can measure substrate (or product) concentrations and the total concentration of enzyme [E] t. [E] t = [E] + [ES] = free enzyme + enzyme in complex with substrate (2) Thus, we want to express the rate, v, in terms of substrate concentration [S], and total enzyme concentration [E] t.

6 K s = k -1 /k 1 = [E][S]/[ES] E + S ES E + P k1k1 k-1k-1 k2k2 From this equation: Under certain circumstances (if k -1 >>k 2 ), E and S are in equilibrium with ES, with an equilibrium dissociation constant K s. However, this assumption is not always valid, thus it is of more general use to introduce the concept of the steady state.

7 In steady state, the rates of formation and breakdown of [ES] are equal: k 1 [E][S] = k -1 [[ES] + k 2 [ES] Rearrange to give [ES] = (k 1 /k -1 +k 2 )[E][S] Define a constant K m = (k -1 +k 2 / k 1 ) K m [ES] = [E][S] (3) Recall we want to get a formula with measurable quantities [S] and [E] t Rearrange equation 2 (solve for [E]) and plug into 3 to get: K m [ES] = [E] t [S] – [ES][S]

8 Transfer second term on right side to left side to get: [ES](K m + [S]) = [E] t [S] Rearrange to [ES] = [E] t [S]/(K m + [S]) Using equation 1 we can finally solve for v, velocity v = k 2 [E] t [S]/(K m + [S]) (4) This formula is referred to as the Michaelis-Menten equation

9 Consider a graph that we can construct from the measurable quantities v and [S] v = change in product change in time Increasing [substrate] At high substrate concentrations, the reaction reaches a Maximum velocity V max, because the enzyme molecules are saturated; every enzyme is occupied by substrate and carrying out the catalytic step [S] = K m

10 From these relationships, consider the following: What is K m and what does it mean? K m is a ratio of rate constants: K m = (k -1 +k 2 / k 1 ) Thus in our catalyzed reaction, if k 2 is much smaller than k -1, K m = k -1 /k 1 = K s, the equilibrium constant for [ES] formation. In this case, a large K m means k -1 >>k 1, thus the enzyme binds the substrate very weakly. However, in a separate instance a large k 2 can have a similar effect on K m. Thus, what is the utility of K m ?

11 The most useful way to think of K m is reflected in the plot of a reaction that follows the Michaelis-Menten equation

12 In this plot, K m is numerically equal to the substrate Concentration at which the reaction velocity equals half of its maximum value. Where [S] = K m, the Michaelis-Menton equation simplifies to v = V max /2 Thus, an enzyme with a high K m requires a higher substrate concentration to achieve a given reaction velocity than an enzyme with a low K m.

13 What are some enzyme’s K m ’s

14 In considering Vmax mathematically, by making [S] much larger than K m the Michaelis-Menten equation simplifies to: V max = k 2 [E] t Thus, another way of writing the Michaelis-Menten rate Equation is: v = V max [S] / (K m + [S]) Typically, all of this is an oversimplification, and enzyme- Mediated catalysis looks more like: E + S ES EP E + P k1k1 k-1k-1 k2k2 k3k3

15 In this more complex system, k 2 must be replaced with a more general constant, called k cat v = k cat [E] t [S]/ (K m + [S]) In the two step reaction we considered first, k cat = k 2. For more complex reactions, k cat is a combination of rate constants for all reactions between ES and E + P.

16 k cat is a rate constant that reflects the maximum number of molecules of substrate that could be converted to product each second per active site. Because the maximum rate is obtained at high [S], when all the active sites are occupied with substrate, k cat (the turnover number) is a measure of how rapidly an enzyme can operate once the active site is filled. k cat = V max /[E] t

17 What are some k cat values?

18 Under physiological conditions, enzymes usually do not operate under saturating substrate conditions. Typically, the ratio of [S] to K m is in the range of 0.01-1.0. When K m >> [S], the Michaelis-Menten equation simplifies to: v = k cat /K m ([E] t [S]) The ratio k cat /K m is referred to as the specificity constant which indicates how well an enzyme can work at low [S]. The upper limit of k cat /K m is in the range of 10 8 to 10 9 due to limits of diffusion theory.

19 Both kinetic parameters contribute to enzyme efficiency

20 Lineweaver-Burk plots are convenient for determination of K m and k cat

21 Lineweaver-Burk plots result from taking a double reciprocal of the Michaelis-Menten equation. v = V max [S] / (K m + [S]) 1/v = K m /(V max [S]) + 1/V max Plotting 1/v on the y-axis and 1/[S] on the x-axis (both known quantities) The slope is equal to K m /V max, the y-intercept is 1/V max And the x-intercept is –1/K m

22 Kinetics of enzymes with multiple substrates OrderedPing-Pong

23 Reversible inhibition

24 Reversible / non-covalent

25 Mixed inhibitors bind both E and ES

26 Non-competitive is special mixed inhibition Non-competitive

27 Inhibition effects on kinetic constants

28 Irreversible inhibition destroy enzyme function Suicide inactivators

29 Regulation of metabolic enzymes is key for the cell In metabolic pathways, there is at least one enzyme that sets the rate of flux through the pathway because it catalyzes the slowest or rate- limiting step These steps can be modulated through interactions with other cellular components leading to increased or decreased activities, allowing cells to adjust to changing metabolic conditions

30 Enzyme modification can alter their activity Types of modification –Reversible, non-covalent binding of regulatory compounds or proteins Enzymes modified in this manner are called Allosteric – threonine dehydratase is an example –Reversible, covalent modification such as phosphorylation (LHCII in chloroplasts) –Activation via proteolytic cleavage

31 Allosteric enzymes exist in different “states”

32 Modulators can be stimulatory or inhibitory A stimulator or activator is often the substrate itself (homotropic) When the modulator is a molecule other than the substrate the enzyme is said to be heterotropic Note that allosteric enzymes don’t necessarily have just active sites, but include other sites for modulator binding Only in homotropic enzymes are active sites also regulatory sites

33 Enzymes can be covalently modified with a wide assortment of groups Phosphoryl, adenylyl, methyl, etc. One third to one half of all proteins in a eukaryotic cell are phosphorylated Tyrosine, serine, threonine, and histidine are known amino acids to accept phosphate groups from enzymes known as protein kinases

34 Properties of allosteric enzymes Sigmoidal instead of hyperbolic Michaelis- Menten plots Reflects cooperative interactions between multiple subunits (allosteric enzymes often contain multiple subunits)

35 Substrate-activity curves for allosteric enzymes

36 Substrate binding influences rates of activity Cooperativity Hysteresis

37 Phosphorylation regulates glycogen phosphorylase Catalyzes the removal of a glucose from the polymer glycogen in the form of G1P Although covalent – reversible

38 Some enzymes are made as inactive precursors These inactive precursors are called zymogens or proproteins For instance, the serine proteases involved in insect immunity (Kanost) are synthesized as zymogens and are active only following cleavage In addition, these enzymes are also regulated by interactions with other cellular proteins

39 Activation by subtraction

40 Naturally, biology is more complicated than one enzyme exhibiting one mode of regulation. Enzymes can be regulated by multiple mechanisms!


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