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7.3 Find Measures of Central Tendency and Dispersion p. 259.

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Presentation on theme: "7.3 Find Measures of Central Tendency and Dispersion p. 259."— Presentation transcript:

1 7.3 Find Measures of Central Tendency and Dispersion p. 259

2 Vocabulary Statistics: numerical values used to summarize and compare sets of data Statistics: numerical values used to summarize and compare sets of data Measure of central tendency: number used to represent the center or middle set of data Measure of central tendency: number used to represent the center or middle set of data –Mean - the average –Median – the middle number –Mode – number that occurs most

3 Vocabulary Measure of Dispersion: statistic that tells you how spread out the values are Measure of Dispersion: statistic that tells you how spread out the values are –Range – biggest - smallest –Standard Deviation: “sigma”

4 EXAMPLE 1 Find measures of central tendency Waiting Times The data sets at the right give the waiting times (in minutes) of several people at two veterinary offices. Find the mean, median, and mode of each data set. SOLUTION Median: 20 Mode: 24 9 198 = 22 = Office A : Mean: x = 14 + 17 + + 32 9 … = 16 Median: 18 Mode: 18 9 Office B : Mean: x = 8 + 11 + + 23 … 9 = 144

5 GUIDED PRACTICE for Example 1 TRANSPORTATION 1. The data set below gives the waiting times (in minutes) of 10 students waiting for a bus. Find the mean, median, and mode of the data set. 4, 8, 12, 15, 3, 2, 6, 9, 8, 7 Mean: x = 10 4 + 8 + 12 + + 7 … SOLUTION 10 = 74 = 7.4 Median: 7.5 Mode: 8

6 EXAMPLE 2 Find ranges of data sets Find the range of the waiting times in each data set. Explain what that means. SOLUTION Office A: Range = 32 – 14 Office B: Range = 23 – 8 Because the range for office A is greater, its waiting times are more spread out. = 18 = 15

7 EXAMPLE 3 Standardized Test Practice Office B: = (8 16) 2 + (11 16) 2 + + (23 16) 2 – – –... 9 = 182 9 4.5 = 290 9 5.7 Office A : = (14 22) 2 – + (17 22) 2 9 + + (32 22) 2... – – ANSWER The correct answer is D.

8 GUIDED PRACTICE for Examples 2 and 3 2.Find the range and standard deviation of the data set. 4, 8, 12, 15, 3, 2, 6, 9, 8, 7 Range = 15 – 2 SOLUTION = 13 = 3.8 Standard deviation


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