1. Periodic table trends Answers THE 9 TH CIRCUIT COURT OF APPEALS DESEGREGATES THE PERIODIC TABLE OF ELEMENTS

2. Answers 2 a) – He, Ne, Ar, Noble gases 2 b) – Li, Na, K, Alkali metals 3 a) – Li, Na, K, Alkali metals 3 b) – He, Ne, Ar, Noble gases 4. As one increases, the other decreases 5. Ionization energy increases Atomic radius decreases 6.Ionization energy decreases Atomic radius increases

3. 7. 11p + 12n ° Na has 11 electrons Na + has 10 electrons Ne has 10 electrons 11p + 12n ° 10p + 10n ° electron configuration of Na + resembles Ne Alkali metals become like noble gases 8.Radius increases because shells are added Increased radius will make it easier to lose an electron because of greater distance between positive and negative charges

4. 9.Proton # increases. More protons means greater attraction between nucleus and outer electron thus higher ionization energy. The greater attraction also means that outer electrons are brought closer to the nucleus, thus smaller atomic radius results. Li (enc = 1) + + + Be (enc = 2) + + + + B (enc = 3) + + + + +

5. 10.Noble gases are ignored 11.Electron affinity is energy associated with an atom gaining an electron. It is highest in the top right where atoms are smallest with the greatest number of protons.

6. Ionization Energy can be summarized as

7. Using only the periodic table, rank the elements in each set by increasing ionization energy a)Xe, He, Ar b)Sn, In, Sb c)Sr, Ca, Ba a)Xe, Ar, He b)In, Sn, Sb c)Ba, Sr, Ca

8. From Friday… What is the trend for EA? Increasing Ionization Energy

9. Using only the periodic table, which element will have the lower EA? a)K or Ca b)O or Li c)S or Se a)K b)Li c)Se

10. From Friday… What is the trend for Atomic Radius?

11. Using only the periodic table, rank the atoms in each set by decreasing atomic size. a)Mg, Be, Ba b)Ca, Se, Ga c)Br, Rb, Kr d)Se, Br, Ca e)Ba, Sr, Cs a)Ba, Mg, Be b)Ca, Ga, Se c)Rb, Br, Kr d)Ca, Se, Br e)Cs, Ba, Sr

12. Complete the following questions from your textbook. p. 60 #1-6