1. Physics 207: Lecture 30, Pg 1 Lecture 30Goals: Review for the final. Review for the final. Final exam on Monday, Dec 20, at 5:05 pm, at Sterling 1310, Graham 19. HW 11 due tonight.

2. Physics 207: Lecture 30, Pg 2 l The figure shows a snapshot graph D(x, t = 2 s) taken at t = 2 s of a pulse traveling to the left along a string at a speed of 2.0 m/s. Draw the history graph D(x = −2 m, t) of the wave at the position x = −2 m. Waves

3. Physics 207: Lecture 30, Pg 3 l History Graph: 2 3 6 4 7 time (sec) 2 -2 5

4. Physics 207: Lecture 30, Pg 4 l A concert loudspeaker emits 35 W of sound power. A small microphone with an area of 1 cm 2 is 50 m away from the speaker. l What is the sound intensity at the position of the microphone? l How much sound energy impinges on the microphone each second?

5. Physics 207: Lecture 30, Pg 5 R P source =35 W R=50 m l The power hitting the microphone is: P microphone = I A microphone

6. Physics 207: Lecture 30, Pg 6 Intensity of sounds l If we were asked to calculate the intensity level in decibels: I 0 : threshold of human hearing I 0 =10 -12 W/m 2

7. Physics 207: Lecture 30, Pg 7 l Suppose that we measure intensity of a sound wave at two places and found them to be different by 3 dB. By which factor, do the intensities differ?

8. Physics 207: Lecture 30, Pg 8 Engines l For the engine shown below, find, W out, Q H and the thermal efficiency. Assume ideal monatomic gas. PiPi 4P i ViVi 2V i Q=90J Q=25J

9. Physics 207: Lecture 30, Pg 9 l First, use the ideal gas law to find temperatures PiPi 4P i ViVi 2V i Q=90J Q=25J TiTi 4T i 8T i 2T i l From the right branch, we have: nC V ΔT=90 J n(3R/2)6T i =90J nRT i =10J

10. Physics 207: Lecture 30, Pg 10 l Work output is the area enclosed by the curve: PiPi 4P i ViVi 2V i Q=90J Q=25J TiTi 4T i 8T i 2T i W out =area=3P i V i =3nRT i =30J

11. Physics 207: Lecture 30, Pg 11 l From energy conservation: W out =Q H -Q C W out =30J Q C =115J η=0.2 l The thermal efficiency is: Q H =145J

12. Physics 207: Lecture 30, Pg 12 The Carnot Engine l All real engines are less efficient than the Carnot engine because they operate irreversibly due to the path and friction as they complete a cycle in a brief time period. l Carnot showed that the thermal efficiency of a Carnot engine is:

13. Physics 207: Lecture 30, Pg 13 l For which reservoir temperatures would you expect to construct a more efficient engine? A) T cold =10 o C, T hot =20 o C B) T cold =10 o C, T hot =800 o C C) T cold =750 o C, T hot =800 o C

14. Physics 207: Lecture 30, Pg 14 Kinetic theory l A monatomic gas is compressed isothermally to 1/8 of its original volume. l Do each of the following quantities change? If so, does the quantity increase or decrease, and by what factor? If not, why not? a. The temperature b.The rms speed v rms c. The mean free path d. The molar heat capacity C V

15. Physics 207: Lecture 30, Pg 15 N/V: particles per unit volume l Mean free path is the average distance particle moves between collisions: l The average translational kinetic energy is: ε avg =(1/2) mv rms 2 =(3/2) k B T C V =3R/2 (monatomic gas) l The specific heat for a monatomic gas is:

16. Physics 207: Lecture 30, Pg 16 l The average kinetic energy of the molecules of an ideal gas at 10°C has the value K 1. At what temperature T 1 (in degrees Celsius) will the average kinetic energy of the same gas be twice this value, 2K 1 ? (A) T 1 = 20°C (B) T 1 = 293°C (C) T 1 = 100°C l Suppose that at some temperature we have oxygen molecules moving around at an average speed of 500 m/s. What would be the average speed of hydrogen molecules at the same temperature? (A) 100 m/s (B) 250 m/s (C) 500 m/s (D) 1000 m/s (E) 2000 m/s

17. Physics 207: Lecture 30, Pg 17 Simple Harmonic Motion l A Hooke’s Law spring is on a horizontal frictionless surface is stretched 2.0 m from its equilibrium position. An object with mass m is initially attached to the spring however, at equilibrium position a lump of clay with mass 2m is dropped onto the object. The clay sticks. What is the new amplitude? k m k m -2 2 0(≡X eq ) 2m

18. Physics 207: Lecture 30, Pg 18 ½ k A 2 =½ m v max 2 v max =ωA l The speed when the mass reaches the equilibrium position: l The speed after clay sticks can be found using momentum conservation: m v max =(m+2m)v new v new =v max /3 l The new amplitude can be found using energy conservation: ½ (m+2m)v new 2 =½ k A new 2 A new =A/√3

19. Physics 207: Lecture 30, Pg 19 Fluids l What happens with two fluids?? Consider a U tube containing liquids of density  1 and  2 as shown: Compare the densities of the liquids: (A)  1 <  2 (B)  1 =  2 (C)  1 >  2 11 22

20. Physics 207: Lecture 30, Pg 20 Fluids l What happens with two fluids?? Consider a U tube containing liquids of density  1 and  2 as shown: At the red arrow the pressure must be the same on either side.  1 x =  2 y  Compare the densities of the liquids: (A)  1 <  2 (B)  1 =  2 (C)  1 >  2 11 22 x y