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Announcements To join clicker to class today: – Turn on the Clicker (the red LED comes on). – Push “Join” button followed by “20” followed by the “Send”

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Presentation on theme: "Announcements To join clicker to class today: – Turn on the Clicker (the red LED comes on). – Push “Join” button followed by “20” followed by the “Send”"— Presentation transcript:

1 Announcements To join clicker to class today: – Turn on the Clicker (the red LED comes on). – Push “Join” button followed by “20” followed by the “Send” button (switches to flashing green LED if successful). Topics in Chapter 5 What's in the Water? ● Exam Results: ● Average about the same ● Spread same ● Will post results early afternoon Review

2 What’s Dissolved in the Water? (a small selection) ~0 mg/kg~0.002 mg/kg (~ 2 µg/kg) ~0 mg/kgCHCl 3 (disinfection by product) ~0 mg/kg~1 mg/kg~0 mg/kg F - (for teeth) ~9 mg/kg O2O2 ~0 mg/kg Deionized Water (ppm) ~31 mg/kg~25 mg/kgSO 4 2- ~4 mg/kg Ni 2+ ~10 mg/kg Na + ~160 mg/kg Ca 2+ (makes water hard) Drinking Water (ppm) Lake Water (ppm) Solute

3 ppm, ppb, ppt units ppm = parts per million – =(10 6 ppm)(mass solute)/(mass of sol’n) –Equivalent to (mg solute)/(kg sol’n) ppb = parts per billion –=(10 9 ppb)(mass of solute)/(mass of sol’n) ppt = parts per trillion –=(10 12 ppt)(mass of solute)/(mass of sol’n)

4 Molarity Molarity (M) = (moles of solute)/(L sol’n) Ex: What is the molarity of the solution made from 35. g of NaCl to make 170 mL of solution. –M (NaCl) = 22.990 + 35.453 = 58.443 g/mole

5 How we use Molarity Ex: Suppose we want to react 1.0 x 10 -5 moles of CaCO 3 (~2 mg) in the following reaction: –H 2 SO 4 (aq)+CaCO 3 (s) ––> CaSO 4 (aq) + H 2 O + CO 2 (g) Converts CaCO 3 into CaSO 4, which is slightly water soluble. How acid rain damages buildings and why limestone would not have lasted near surface of early Earth. –Have a 4.5 x 10 -5 M solution –How many mL of solution do we need?

6 Converting between mg/kg and M Molarity of CHCl 3 (residual from disinfection) in drinking water? –2 µg/kg –M (CHCl 3 )= 119.38 g/mol –D(H 2 O@ 25 ˚C)=0.996 g/ mL


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