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Quiz #3 Define Enzyme Classes Systematic naming –Given a reaction (including names) –Use subclass designation if appropriate Catalytic mechanisms –Define.

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Presentation on theme: "Quiz #3 Define Enzyme Classes Systematic naming –Given a reaction (including names) –Use subclass designation if appropriate Catalytic mechanisms –Define."— Presentation transcript:

1 Quiz #3 Define Enzyme Classes Systematic naming –Given a reaction (including names) –Use subclass designation if appropriate Catalytic mechanisms –Define –How does a given amino acid participate? Discuss protonation state and reaction.

2 Enzyme Kinetics The study of the rates at which enzyme-catalyzed reactions occur.

3 Value of Enzyme Kinetics Quantitation of Enzyme Activity –Purification Competing Substrates and Inhibitors –Suggest physiological functions –Suggest regulatory mechanisms Response to Different Conditions –Reaction mechanism

4 Kinetic Data plus Structure and Mechanism Clues to an enzyme’s biological function Ways to modify an enzyme for therapeutic purposes

5 Enzyme-Catalyzed Reactions are Reversible (Accelerate Attainment of Equilibrium)

6 Elementary Reactions A ——> P Reaction Intermediates A ——> I 1 ——> I 2 ——> P

7 Two-Step Reactions (Rate Determining Step)

8 Chemical Kinetics Can reveal the number of reacting species Can reveal the rate of their interactions Are described by Rate Equations

9 Rate Equations Reaction Order or Molecularity: number of molecules participating in a reaction Velocity (V): molar per second (Ms –1 ) Rate Constant (k): proportional to frequency of interaction between reactants

10 Rate Equations (General Form) aA + bB ——> P V = k[A] a [B] b k = rate constant Order of Reaction = a + b

11 Reaction Order (Reaction Molecularity) First-order or unimolecular Second-order or bimolecular Third-order very rare 4 th -order are unknown

12 Rates of Reactions First-Order Reactions

13 Time Course of Reaction

14 Kinetics of Reactions

15 First-Order Reaction

16 Initial Velocity (V O ) V = k F [S] – k B [P] Initial Velocity (V o ) ([P] = 0) V o = k F [S]

17 Uncatalyzed Reaction

18 Enzyme Catalysis Hyperbolic Relationship V O not proportional to [S]

19 Michaelis-Menten Formulation

20 Enzyme Kinetics Experiment: (1)Mix enzyme + substrate (2)Record rate of product formation as a function of time (the velocity of reaction) (3) Plot initial velocity versus substrate concentration. (4) Change substrate concentration and repeat

21 Postulated Pathway of Enzyme Catalysis: Formation of Enzyme-Substrate Complex

22 Assumptions: Initial Velocities Catalysis is rate limiting V o = k 2 [ES] (rate limiting)

23 Assumptions Binding equilibrium (k –1 >>k 2 ) Steady state (d[ES]dt = 0)

24 Assumptions Binding equilibrium (k –1 >>k 2 ) Steady state (d[ES]dt = 0)

25 Additionally [s]>>>>>>>>>[E-S] –[S] doesn’t change during initial velocity [E T ] = [E F ] + [E-S]

26 Progress Curves (M-M Enzyme) Steady-State Very short

27 Michaelis-Menten Equation V O = V max [S] K m + [S] Assumes All Enzyme Molecules are Catalytically Active

28 Michaelis Constant K M is the substrate concentration at which the reaction velocity is half-maximal High affinity = low K m ; Low Affinity = high K m K m = k -1 + k 2 k 1

29 Michaelis-Menton Enzyme Kinetics

30 Catalytic Constant (Turnover Number) # of substrate converted to product # of enzyme = Unit of time V max = k cat X # of enzymes # can be any units (molecules, moles, μmoles) But all must be the same units

31 Catalytic Efficiency k cat /K M –Limited by diffusion (10 8 to 10 9 M -1 s -1 )

32 Lineweaver-Burk Formulation

33 Lineweaver-Burk Plot

34 Eadie-Hofstee Formulation

35 Eadie-Hofstee Plot

36 A certain enzyme catalyzes the conversion of 100 μmoles of A to B in one second, when the concentration of A is 20 mM. It catalyzes the conversion of 350 μmoles of A to B in one second when the concentration of A is either 500 mM or 550 mM. -Calculate K m -Draw the Michaelis-menton curve and Lineweaver-Burk plot for this enzyme -Can you calculate turnover #?


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