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Aim: How can we use the parallelogram method of adding vectors? Do Now: Find the resultant of the following vectors through graphical means: 90 m/s South.

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Presentation on theme: "Aim: How can we use the parallelogram method of adding vectors? Do Now: Find the resultant of the following vectors through graphical means: 90 m/s South."— Presentation transcript:

1 Aim: How can we use the parallelogram method of adding vectors? Do Now: Find the resultant of the following vectors through graphical means: 90 m/s South 150 m/s East Scale: 1 cm = 30 m/s

2 N S WE

3 N S WE

4 N S WE

5 N S WE 90 m/s

6 N S WE

7 N S WE

8 N S WE 150 m/s

9 N S WE 90 m/s 150 m/s

10 N S WE 90 m/s 150 m/s

11 N S WE 90 m/s 150 m/s

12 N S WE 90 m/s 150 m/s

13 N S WE 5.8 cm x 30 90 m/s 150 m/s

14 N S WE 174 m/s 90 m/s 150 m/s

15 N S WE 174 m/s 90 m/s 150 m/s

16 N S WE 174 m/s 31° South of East 90 m/s 150 m/s

17 N S WE Now solve for the resultant mathematically 90 m/s 150 m/s

18 N S WE (90 m/s) 2 + (150 m/s) 2 = R 2 174.9 m/s = R 90 m/s 150 m/s

19 Two people pull on ropes attached to a box – one with a force of 350 N 35° West of South and one with a force of 420 N 45° South of East. Determine the resultant force on the box. Scale: 1 cm = 70 N

20 N S WE

21 N S WE

22 N S WE

23 N S WE

24 N S WE 35° 350 N

25 N S WE 35° 350 N

26 N S WE 35° 350 N

27 N S WE 35° 350 N

28 N S WE 35° 350 N 45° 420 N

29 N S WE 35° 350 N 45° 420 N

30 N S WE 35° 350 N 45° 420 N

31 N S WE 35° 350 N 45° 420 N

32 N S WE 35° 350 N 45° 420 N

33 N S WE 35° 350 N 45° 420 N

34 N S WE 35° 350 N 45° 420 N

35 N S WE 35° 350 N 45° 420 N

36 N S WE 35° 350 N 45° 420 N

37 N S WE 35° 350 N 45° 420 N Resultant

38 N S WE 35° 350 N 45° 420 N Resultant

39 N S WE 35° 350 N 45° 420 N 8.4 cm x 70 = 588 N Resultant

40 N S WE 35° 350 N 45° 420 N 588 N Resultant

41 N S WE 35° 350 N 45° 420 N 588 N80° South of East Resultant

42 N S WE 35° 350 N 45° 420 N 588 N80° South of East Resultant

43 N S WE 35° 350 N 45° 420 N Now Solve for the magnitude mathematically Use a derivation of the law of cosines R 2 = a 2 + b 2 + 2abcosθ Where θ is the angle between the 2 vectors θ

44 N WE 35° 350 N 45° 420 N R 2 = a 2 + b 2 + 2abcosθ R 2 = (350 N) 2 + (420 N) 2 + 2(350 N)(420 N)cos80 R = 591.6 N S


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