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Geometry 9.5 Inscribed Angles. Inscribed Angles The vertex is on the circle The sides of the angle: AAre chords of the circle IIntercept an arc on.

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Presentation on theme: "Geometry 9.5 Inscribed Angles. Inscribed Angles The vertex is on the circle The sides of the angle: AAre chords of the circle IIntercept an arc on."— Presentation transcript:

1 Geometry 9.5 Inscribed Angles

2 Inscribed Angles The vertex is on the circle The sides of the angle: AAre chords of the circle IIntercept an arc on the circle Inscribed angle Intercepted Arc

3 Inscribed Angle Theorem The measure of the inscribed angle is half the measure of its central angle (and therefore half the intercepted arc). 30 o 60 o 160 o 80 o 160 o

4 A Very Similar Theorem The measure of the angle created by a chord and a tangent equals half the intercepted arc. 50 o 100 o tangent chord 70 o t a n g e n t c h o r d 35 o

5 Corollary If two inscribed angles intercept the same arc, then the angles are congruent. xy x = y ~ sf giants sf = giants ~

6 Corollary If an inscribed angle intercepts a semicircle, then it is a right angle. diameter Why? diameter 180 o 90 o

7 Corollary If a quadrilateral is inscribed in a circle, then opposite angles are supplementary. 70 o 110 o 95 o 85 o supplementary

8 Solve for the variables. O yy 20  110  xx O yy 20  xx 60  140  O yy xx 1. 2. 3. 40 o 150 o 75 o Angle x and the 20 o angle intercept the same arc. Semicircle 20 o 90 o x = 40 o y = 75 o x = 20 o y = 90 o 120 o x = 60 o 140 o 100 o y = 50 o

9 Solve for the variables. O xx 80  yy O xx yy zz O xx zz yy 82  4. 5. 6. x = 40 o Part of semicircle 100 o y = 50 o x and y both intercept a semicircle. x = 90 o y = 90 o 180 o z = 90 o y + 82 o + z = 180 o y + z = 98 o The red and orange arcs are congruent (they have congruent chords). y = 49 o Thus, y and z are congruent angles (they intercept the red and orange arcs). z = 49 o Inscribed Quadrilateral supplementary x = 98 o

10 Find x and the measure of angle D. A B C D 5x 8x x2x2 A B C D 4x 15x 50  x2x2 7. 8. Inscribed Quadrilateral supplementary X 2 + 8x = 180 X 2 + 8x - 180 = 0 ( )( ) = 0x + x - 18 10 x + 18 = 0 and x – 10 = 0 x = -18 and x = 10 If x is negative, this angle would have a negative value. 100 o X 2 + 15x = 100 X 2 + 15x - 100 = 0 ( )( ) = 0x + x - 20 5 x + 20 = 0 and x – 5 = 0 x = -20 and x = 5 If x is negative, this angle would have a negative value.

11 HW P. 352-355 CE #1-9 WE #1-9, 19-21


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