1. Velocity and Displacement with Acceleration Worksheet assistance
Physics
Velocity and Displacement with Acceleration
Worksheet assistance

2. Question #8
In 1994, a human-powered submarine was designed in Boca Raton, Florida. It achieved a maximum speed of 3.06 m/s. Suppose this submarine starts from rest and accelerates at m/s2 until it reaches maximum speed. The submarine then travels at constant speed for another 5.00 s. Calculate the total distance traveled by the submarine
x = ?
vi = 0 m/s
vf = 3.06 m/s
a = .8 m/s2

3. Question #8, continued Since we don’t have a time element, I will use
vf2 = vi2 + 2ax
3.062 = 0 + 2(.8)x
9.36 = 1.6x
5.85 m = x
AND THEN, it travels with a constant speed for 5s
a = 0 m/s2
v = x/t  x = vt = (3.06)(5) = 15.3 m
Total distance travelled: = m

4. Question #11
The world’s fastest warship belongs to the United States Navy. This vessel, which floats on a cushion of air, can move as fast as 1.7 × 102 km/h. Suppose that during a training exercise the ship accelerates m/s2, so that after 15.0 s its displacement is × 102 m. Calculate the ship’s initial velocity just before the acceleration. Assume that the ship moves in a straight line
a = 2.67 m/s2
t = 15 s
x = 600 m
vi = ??

5. Question #11, continued I will use the formula x = xi + vit + ½ at2
20 m/s =

6. Question #15
In 1991, four English teenagers built an electric car that could attain a speed 30.0 m/s. Suppose it takes 8.0 s for this car to accelerate from m/s to 30.0 m/s. What is the magnitude of the car’s acceleration?
vi = 18 m/s
vf = 30 m/s
t = 8 s
a = ??

7. Question #15, continued
Since displacement is not an issue here, I can use a simpler formula:
a = (vf – vi) / t
a = (30 – 18) / 8
a = 12/ 8
a = 1.5 m/s2