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9-6 Area of Irregular Figures Course 2 Math Minute Math Minute Lesson Presentation Lesson Presentation Vocabulary.

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Presentation on theme: "9-6 Area of Irregular Figures Course 2 Math Minute Math Minute Lesson Presentation Lesson Presentation Vocabulary."— Presentation transcript:

1 9-6 Area of Irregular Figures Course 2 Math Minute Math Minute Lesson Presentation Lesson Presentation Vocabulary

2 Math Minute Find the area of the following figures. 1. A triangle with a base of 12.4 m and a height of 5 m 2. A parallelogram with a base of 36 in. and a height of 15 in. 3. A square with side lengths of 2. yd 31 m 2 540 in 2 Course 2 9-6 Area of Irregular Figures 4 yd 2

3 Learn to find the area of irregular figures. Course 2 9-6 Area of Irregular Figures

4 You can find the area of an irregular figure by separating it into non- overlapping familiar figures. The sum of the areas of these figures is the area of the irregular figure. You can also estimate the area of an irregular figure by using graph paper. Course 2 9-6 Area of Irregular Figures

5 Example 1 Estimate the area of the figure. Each square represents one square yard. Count the number of filled or almost-filled squares: 11 red squares. Count the number of squares that are about half-full: 8 green squares. Add the number of filled squares plus ½ the number of half-filled squares: 11 + ( 8) = 11 + 4 =15. 1212 The area of the figure is about 15 yd. 2 Course 2 9-6 Area of Irregular Figures

6 Example 2: Finding the Area of an Irregular Figure Find the area of the irregular figure. Use 3.14 for . Use the formula for the area of a rectangle. Substitute 8 for l. Substitute 9 for w. A = lw A = 8 9 A = 72Step 1: Separate the figure into smaller, familiar figures. 3 yd Course 2 9-6 Area of Irregular Figures 9 yd Step 2: Find the area of each smaller figure. Area of the rectangle: 8 yd 9 yd

7 Continued Find the area of the irregular figure. Use 3.14 for . Substitute 2 for b and 9 for h. Course 2 9-6 Area of Irregular Figures Area of the triangle: A = bh 1 2 __ The area of a triangle is the b h. 1212 A = (2 9) 1 2 __ A = (18) 1 2 __ Multiply. A = 9 2 yd 9 yd 8 yd 9 yd

8 Now You Try… Find the area of the irregular figure. Use 3.14 for . Use the formula for the area of a parallelogram. Substitute 16 for b. Substitute 9 for h. A = bh A = 16 9 A = 144Step 1: Separate the figure into smaller, familiar figures. 16 m Course 2 9-6 Area of Irregular Figures 9 m 16 m Step 2: Find the area of each smaller figure. Area of the parallelogram:

9 Continued Find the area of the irregular figure. Use 3.14 for . Substitute 3.14 for  and 8 for r. 16 m Course 2 9-6 Area of Irregular Figures 9 m 16 m Area of the semicircle: A = (r) 1 2 __ The area of a semicircle is the area of a circle. 1212 A ≈ (3.14 8 2 ) 1 2 __ A ≈ (200.96) 1 2 __ Multiply. A ≈ 100.48

10 Additional Example 2 Continued Find the area of the irregular figure. Use 3.14 for . A ≈ 144 + 100.48 = 244.48The area of the figure is about 244.48 m 2. Step 3: Add the area to find the total area. 16 m Course 2 9-6 Area of Irregular Figures 9 m 16 m

11 Continued Find the area of the irregular figure. Use 3.14 for . A = 72 + 9 = 81The area of the figure is about 81 yd 2.Step 3: Add the area to find the total area. Course 2 9-6 Area of Irregular Figures

12 Example 3: Finding the Shaded Region Find the area of the shaded region Use 3.14 for pi. Course 2 9-6 Area of Irregular Figures 2 cm 4 cm Step 1: Write the formula. Step 2: Substitute values. A = area of square – area of circle A = (l x w) – ( πr 2 ) A = (4 x 4) – (3.14 x 2 2 ) A = (16) – (3.14 x 4) Step 3: Solve. A = (16) – (12.56) A = 3.44 cm 2


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