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A jogger runs 145m in a direction 20

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Presentation on theme: "A jogger runs 145m in a direction 20"— Presentation transcript:

1 A jogger runs 145m in a direction 20
A jogger runs 145m in a direction 20.0 degrees east of north (vector A), and then runs 105m in a direction 35.0 degrees south of east (vector B). Using components, determine the magnitude and direction of the resultant vector C for these two displacements.

2 A jogger runs 145m in a direction 20
A jogger runs 145m in a direction 20.0 degrees east of north (vector A), and then runs 105m in a direction 35.0 degrees south of east (vector B). Using components, determine the magnitude and direction of the resultant vector C for these two displacements.

3 A jogger runs 145m in a direction 20
A jogger runs 145m in a direction 20.0 degrees east of north (vector A), and then runs 105m in a direction 35.0 degrees south of east (vector B). Using components, determine the magnitude and direction of the resultant vector C for these two displacements.

4

5 Sin 20 = Ax / 145 Ax = 49.6 m Cos 35 = Bx/105 Bx = 86.0 m Ax + Bx = m

6 cos 20 = Ay / 145 Ay = m sin 35 = Bx/105 By = 60.2 m Ay - By = 75.8 m

7 = C2 C = 155m tan angle = 75.8/135.6 angle = 29 degrees


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