1. Order of Operations: Parenthesis Exponents (including roots) Multiplication & Division Addition & Subtraction Always Work Left to Right

3. Review: Properties of Arithmetic

7. 3, 2, 1… Lets work some problems!

8. 9 + 6 ÷ (2 - 8)

9. Answer: 8

10. 6 · 6 - (7 + 5)

11. Answer: 24

12. 2 - (2 + 3 - 8)

13. Answer: 5

14. -3 - (-4)(-5) - (-6)

15. Answer: -17

16. Reciprocal & Multiplicative Inverse Property If one fraction is the inverted (upside down) form of another fraction, each of the fractions is said to be the RECIPROCAL of the other fraction. For example: 3/2 is the reciprocal of 2/3 -4/11 is the reciprocal of -11/4 1/4 is the reciprocal of 4 -5 is the reciprocal of -1/5 1/0 is MEANINGLESS and therefore ZERO is the ONLY real number which DOES NOT have a RECIPROCAL. If a number is multiplied by its reciprocal the PRODUCT is the number 1.

17. Definition: For any nonzero real number a, the RECIPROCAL, or MULTIPLICATIVE INVERSE, of the number is 1/a.

20. Evaluate: 4 ÷ ¼

21. Answer: 16

22. Challenging Problems

23. 8 · (5 – 7)⁴ + 2 · 3² ÷ 2 - 3 3

24. Answer: 110

25. 2 (10² + 3 · 19) ÷ (-5² ÷ ¼)

26. Answer: -3.14

27. (39 + 2)(83 - 4)

28. Answer: 3239

29. Distributive Property

30. Vocabulary The Distributive Property is a mathematical property that allows you to multiply a number on the outside of the parentheses by each number inside the parentheses.

31. What does it look like? 5(2 + 4) = 5(2) + 5(4) Multiply the 5 by EVERYTHING in the parentheses!! 5(6) = 10 + 20 30 = 30 (2 + 3)6 = (2)(6) + (3)(6) (5)(6) = (12) + (18) a(b + c) = a(b) + a(c) a(b + c) = ac + ab (a + b)c = (a)(c) + (b)(c) (a +b)c = ac + bc

32. It works with subtraction in the Parentheses too! 5(6 – 3) = 5(6) – 5(3) Multiply the 5 everything in the parentheses! 5(3) = 30 – 15 15 = 15 (12 – 3)(-4) = (12)(-4) – (3)(-4) (9)(-4) = -48 - (-12) -36 = -36 a(b – c) = a(b) – a(c) (a – b)c = a(c) – b(c)

33. Use the Distributive Property to Simplify Find 20(102)  20(102) = 20(100 + 2) = 20(100) + 20(2) = 2,000 + 40 = 2,040 Find 53(40)  53(40) = (50 + 3)(40) = (50)(40) + 3(40) = 2000 + 120 = 2,120 Find 9(199)  9(199) = 9(200 – 1) = 9(200) – 9(1) = 1800 – 9 = 1,791

34. Let’s try some more problems…

35. Simplify:  7(b + 2) 7b + 7(2) 7b + 14  4(x + 1) 4x + 4(1) 4x + 4  (-2)(3 + x) (-2)(3) + (-2)x -6 + (-2x) -6 – 2x  2(x – 4) 2x – (2)(4) 2x - 8  (-3)(4 – y) (-3)(4) – (-3)(y) -12 – (-3y) -12 + 3y  (4n-6)5 (4n)(5) – 6(5) 20n - 30

36. More Problems…  12(a + 3) 12a + 12(3) 12a + 36  (c-4)(-2) c(-2) – 4(-2) -2c – (-8) -2c + 8  5(x + y) 5x + 5y  4(x + y + z) 4x + 4y + 4z  -(x +2) (-1)(x + 2) (-1)x + (-1)(2) -x - 2

37. Let’s put our thinking cap on…

38. Recall the distributive property of multiplication over addition... symbolically: a × (b + c) = a × b + a × c and pictorially (rectangular array area model): a × ba × ca bc

39. An example: 6 x 13 using your mental math skills... symbolically: 6 × (10 + 3) = 6 × 10 + 6 × 3 and pictorially (rectangular array area model): 6 × 106 × 36 103

40. What about 12 x 23? Mental math skills? (10+2)(20+3) = 10 × 20 + 10 × 3 + 2 × 20 + 2 × 3 10 × 20 10 × 3 10 203 2 × 32 × 322 × 20 200 30 40 + 6 276

41. And now for multiplying binomials (a+b) × (c+d) = a × (c+d) + b × (c+d) = a × c + a × d + b × c + b × d a × c a × d a c d b × db × dbb × c

42. We note that the product of the two binomials has four terms – each of these is a partial product. We multiply each term of the first binomial by each term of the second binomial to get the four partial products. Product of the FIRST terms of the binomials Product of the OUTSIDE terms of the binomials Product of the INSIDE terms of the binomials Product of the LAST terms of the binomials F + O + I + L ( a + b )( c + d ) = ac + ad + bc + bd Because this product is composed of the First, Outside, Inside, and Last terms, this pattern is often referred to as FOIL method of multiplying two binomials. Note that each of these four partial products represents the area of one of the four rectangles making up the large rectangle.

43. Are the two expressions equal? (y/n) give answer to both expressions (5+6)² 5² + 6²

44. Answer: NO! 121 ≠ 61

45. How to expand a sum: “FOIL” (x+1)² = (x+1)·(x+1) x·(x+1) + 1·(x+1) x·x +(x)·(1) +(1)·(x) + 1·1 x² + x + x + 1² x² + 2x + 1

46. Challenging Problems

47. (101)²

48. Answer: 10,201

49. (7+5)² -7² - 5²

50. Answer: 70

51. (99)(101)

52. Answer: 9999

53. Expand the following algebraic expression: (x+3)²

54. Answer: x² + 6x + 9