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Pg. 30/42 Homework Pg. 42 #9 – 14, 20 – 36 even, 43, 46, 49, 53 #15D= (-∞, 3)U(3, ∞); R = (-∞,0)U(0, ∞)#17D= (-∞, ∞); R = [0, ∞) #19D= (-∞, 8]; R = [0,

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Presentation on theme: "Pg. 30/42 Homework Pg. 42 #9 – 14, 20 – 36 even, 43, 46, 49, 53 #15D= (-∞, 3)U(3, ∞); R = (-∞,0)U(0, ∞)#17D= (-∞, ∞); R = [0, ∞) #19D= (-∞, 8]; R = [0,"— Presentation transcript:

1 Pg. 30/42 Homework Pg. 42 #9 – 14, 20 – 36 even, 43, 46, 49, 53 #15D= (-∞, 3)U(3, ∞); R = (-∞,0)U(0, ∞)#17D= (-∞, ∞); R = [0, ∞) #19D= (-∞, 8]; R = [0, ∞)#21D= (-1, ∞); R = (0, ∞) #23D= (-∞, ∞); R = [-16.25, ∞)#28, 34Graphs #46Graph#53 ; (0, 40) #5-8/3#6-13/4 #74/5#8-3 #19y = (3/2)x + (3/2)#21y = 5 #23y = (3/2)x + 2#25y = (1/5)x – (2/3) #27y = 3; x = -2#29y = (3/2)x #31y = (1/4)x + (1/4)#33y = (3/2)x + 3 #42y = (3/5)x + (17/5)#44y = (-1/2)x + 1 #45y = (1/4)x + (9/2)

2 1.4 Linear Functions and Inequalities Slope The slope of a line through two non-vertical points (x 1, y 1 ) and (x 2, y 2 ) is given by: Find the slope from the given information. – > (-3, 2) (-1, -2) – > (1, 2) (-3, 2) – > (4, -5) (4, 5)

3 1.4 Linear Functions and Inequalities Parallel and Perpendicular If m = a The parallel slope is: The perpendicular slope is: Horizontal and Vertical Lines Horizontal lines: – Slope?? – Equation?? Vertical lines: – Slope?? – Equation?? Find an equation of the line which passes through the points (5, 7) and (5, -8).

4 1.4 Linear Functions and Inequalities Slope-Intercept Form The graph of a straight line is easily described as: Re-write the equation 3x + 5y = 12 to find the slope and y – intercept. Sketch a complete graph. Point-Slope Form You can find the equation of a line using the slope and one ordered pair (a point). Find an equation of the line which passes through the point (5, -2) and has a slope of –½.

5 1.4 Linear Functions and Inequalities General Form Also known as Standard Form: – Given that A, B, and C are whole numbers – Given that A is positive Rewrite y = ¼x – 7 in general form. Practice Find an equation of the line which passes through the point (4, -3) and is perpendicular to the line 2x – 5y = 20. Find an equation of the perpendicular bisector of the segment between the points (6, -3) and (2, 5).

6 1.3 Functions A rocket is shot straight up from the ground with an initial velocity of 128 ft/sec. – At what time will the rocket be 80 ft above the ground? – What is the maximum height and how long does it take to reach the maximum height? The general formula for projectile motion is:

7 Quiz Topics Remember, this quiz is all of 1.1 – 1.3, therefore all classwork and homework since the beginning of school is fair game!! General Topics – Definitions – Evaluating a function Graphically From an equation – Absolute Values – Piecewise equations – Domain and Range – Midpoint – Distance – Word problems!! – Solving – Graphing


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