Download presentation

Presentation is loading. Please wait.

Published byAbigail Cruz Modified over 3 years ago

1
VALs Progress VAL's Progress: The Automatic Validation Tool for PDDL2.1 used in the International Planning Competition Richard Howey and Derek Long University of Durham

2
VALs Progress Introduction VAL was the validation tool used in the 3rd IPC. VAL is evolving along side PDDL to validate plans written in PDDL. The latest development is to extend VAL to validate plans with continuous effects. Validating plans with continuous effects is an important first step to developing planners capable of handling continuous effects.

3
VALs Progress Validation Example: Generator and Tanks Initial State and Problem: A generator must run continuously for 100 time units.A generator must run continuously for 100 time units. The generator has a capacity of 60 fuel units, using 1 fuel unit for every 1 time unit to generate.The generator has a capacity of 60 fuel units, using 1 fuel unit for every 1 time unit to generate. Two fuel tanks with 25 fuel units each can refuel the generator while it is generating.Two fuel tanks with 25 fuel units each can refuel the generator while it is generating. The generator starts with a full tank of fuel.The generator starts with a full tank of fuel.

4
VALs Progress Durative Actions Generate: Duration: must be 100 time units.Duration: must be 100 time units. Invariant condition: fuel-level of generator must be greater than zero.Invariant condition: fuel-level of generator must be greater than zero. Continuous Effect:Continuous Effect: Refuel: Duration: less or equal to time to empty tank.Duration: less or equal to time to empty tank. Invariant condition: fuel-level of generator must be less than the capacity of the generator.Invariant condition: fuel-level of generator must be less than the capacity of the generator. Continuous Effects:Continuous Effects: dr/dt = 1 df/dt = 2 k(f) ( k(f) r – f(0) ) dg/dt = 2 k(f) ( f(0) – k(f) r ) dg/dt = – 1 t = time since durative action began g = fuel-level of generator f = fuel-level of a tank k(f) = flow constant of tank f

5
VALs Progress Possible Plan 1: (generate generator) [100] 20: (refuel generator tank1) [25] 80: (refuel generator tank2) [12.5] generate refuel 1refuel 2

6
VALs Progress Plan to Validate 1: (generate generator) - 1: (generate generator) - start 20: (generate generator) 20: Invariant for (generate generator) 20: 20: Update of Continuously Changing Primitive Numerical Expressions 20: (refuel generator tank1) - 20: (refuel generator tank1) - start 45: (generate generator) 45: Invariant for (generate generator) (refuel generator tank1) Invariant for (refuel generator tank1) 45: 45: Update of Continuously Changing Primitive Numerical Expressions 45: (refuel generator tank1) - 45: (refuel generator tank1) - end 101: (generate generator) 101: Invariant for (generate generator) 101: 101: Update of Continuously Changing Primitive Numerical Expressions 101: (generate generator) - 101: (generate generator) - end

7
VALs Progress Time 1 upto 20 1: (generate generator) - 1: (generate generator) - start 20: (generate generator) 20: Invariant for (generate generator) 20: 20: Update of Continuously Changing Primitive Numerical Expressions t = time since last simple action g = fuel-level of generator g(t) = – t + 60 for t in [0,19) Invariant g(t) > 0 for t in (0,19) Update Update Generator fuel-level: g(19) = –19 + 60 = 41 dg/dt = – 1 – t + 60 > 0 for t in (0,19)

8
VALs Progress Time 20 upto 45 20: (refuel generator tank1) - 20: (refuel generator tank1) - start 45: (generate generator) 45: Invariant for (generate generator) (refuel generator tank1) Invariant for (refuel generator tank1) 45: 45: Update of Continuously Changing Primitive Numerical Expressions 45: (refuel generator tank1) - 45: (refuel generator tank1) - end t = time since last simple action g = fuel-level of generator a = fuel-level of tank 1 dg/dt = – 1 dr/dt = 1 da/dt = 0.08r – 2 dg/dt = – 0.08r + 2 dg/dt = – 0.08t + 1 g(t) = – 0.04t 2 + t + 41 for t in [0,25) r(t) = t for t in [0,25) a(t) = 0.04t 2 – 2t + 25 for t in [0,25)

9
VALs Progress Time 20 upto 45 Invariants Update g(25) = – 0.04 25 2 + 25 + 41 = 41, a(25) = 0 g(t) > 0 for t in [0,25) – 0.04t 2 + t + 41 > 0 for t in [0,25) g(t) 60 for t in (0,25) – 0.04t 2 + t + 41 60 for t in (0,25) 0.04t 2 – t + 19 0 for t in (0,25) t = time since last simple action g = fuel-level of generator

10
VALs Progress Time 45 upto 80 80: (generate generator) 80: Invariant for (generate generator) 80: 80: Update of Continuously Changing Primitive Numerical Expressions t = time since last simple action g = fuel-level of generator g(t) = – t + 41 for t in [0,35) Invariant g(t) > 0 for t in [0,35) Update Update Generator fuel-level: g(35) = – 35 + 41= 6 dg/dt = – 1 – t + 41 > 0 for t in [0,35)

11
VALs Progress Time 80 upto 92.5 80: (refuel generator tank2) - 80: (refuel generator tank2) - start 92.5: (generate generator) 92.5: Invariant for (generate generator) (refuel generator tank2) Invariant for (refuel generator tank2) 92.5: 92.5: Update of Continuously Changing Primitive Numerical Expressions 92.5: (refuel generator tank2) - 92.5: (refuel generator tank2) - end t = time since last simple action g = fuel-level of generator b = fuel-level of tank 2 dg/dt = – 1 dr/dt = 1 db/dt = 0.32r – 4 dg/dt = – 0.32r + 4 dg/dt = – 0.32t + 3 g(t) = – 0.16t 2 + 3t + 6 for t in [0,12.5) r(t) = t for t in [0,12.5) b(t) = 0.16t 2 – 4t + 25 for t in [0,12.5)

12
VALs Progress Time 80 upto 92.5 Invariants Update Update Generator and Tank fuel-levels: g(12.5) = 18.5, b(12.5) = 0 g(t) > 0 for t in [0,12.5) – 0.16t 2 + 3t + 6 > 0 for t in [0,12.5) g(t) 60 for t in (0,12.5) – 0.16t 2 + 3t + 6 60 for t in (0,12.5) 0.16t 2 – 3t – 54 0 for t in (0,12.5) t = time since last simple action g = fuel-level of generator

13
VALs Progress Time 92.5 upto 101 101: (generate generator) 101: Invariant for (generate generator) 101: 101: Update of Continuously Changing Primitive Numerical Expressions 101: (generate generator) - 101: (generate generator) - end g(t) = – t + 18.5 for t in [0,8.5) Invariant g(t) > 0 for t in [0,8.5) Update Update Generator fuel-level: g(8.5) = – 8.5 + 18.5 = 10 dg/dt = – 1 – t + 18.5 > 0 for t in [0,8.5)

14
VALs Progress Goal

15
LaTeX Report Plan Plan to validate Plan validation Diagrams See handouts for generator validation report

16
VALs Progress Gantt Chart Actions of different executives can be displayed on different rows

17
VALs Progress Graphs Graphs of the primitive numerical expressions are plotted for the duration of the plan.

18
VALs Progress Conclusions Restrictions on types of continuous effects are required to guarantee validation of plans: all continuous effects must be polynomial Validating plans with continuous effects is an important first step to developing planners capable of handling continuous effects.

Similar presentations

Presentation is loading. Please wait....

OK

LIAL HORNSBY SCHNEIDER

LIAL HORNSBY SCHNEIDER

© 2017 SlidePlayer.com Inc.

All rights reserved.

Ads by Google

Ppt on national education day speech Ppt on cobb douglas production function Ppt on relation and function free download Ppt on provident fund act 1952 Ppt on e-mail spam Ppt on quality education data Ppt on principles of object-oriented programming advantages Ppt on regional trade agreements notified Ppt on cartesian product database Ppt on personality development of students