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PARABOLAS Do Now: Questions 1-9 find the equation of each parabola and name the transformation from x 2.

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Presentation on theme: "PARABOLAS Do Now: Questions 1-9 find the equation of each parabola and name the transformation from x 2."— Presentation transcript:

1 PARABOLAS Do Now: Questions 1-9 find the equation of each parabola and name the transformation from x 2

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3 Things to know about parabolas A parabola is the set of all points equidistant from a fixed line, called the Directrix, and a fixed point not on the line, called the focus. Equation of a parabola y = a(x - h) 2 + k The vertex is at point (h, k) The axis of symmetry is the line x = h The graph of y = ax 2 opens upward if a > 0 and downward if a < 0. The larger the value of | a | is, the narrower the graph of the parabola is.

4 TIME FOR THE HARD STUFF An object is launched at 19.6 meters per second (m/s) from a 58.8-meter tall platform. The equation for the object's height s at time t seconds after launch is s(t) = –4.9t 2 + 19.6t + 58.8, where s is in meters. When does the object strike the ground?

5 STUDENT WORK

6 ANSWER 0 = –4.9t 2 + 19.6t + 58.8 0 = t 2 – 4t – 12 0 = (t – 6)(t + 2) The object strikes the ground six seconds after launch.

7 #2 #2 An object in launched directly upward at 64 feet per second (ft/s) from a platform 80 feet high. What will be the object's maximum height? When will it attain this height?

8 STUDENT WORK

9 ANSWER Equation: s(t) = –16t 2 + 64t + 80 h = –b / 2a = –(64)/2(–16) = –64/–32 = 2 k = s(2) = –16(2) 2 + 64(2) + 80 = –16(4) + 128 + 80 = 208 – 64 = 144 It takes two seconds to reach the maximum height of 144 feet.

10 Notes On “Projectile Problems” s(t) represents the projectile's instantaneous height at any time t v o represents initial velocity t represents time in seconds after the projectile is released

11 EXAMPLE A ball is thrown directly upward from an initial height of 200 feet with an initial velocity of 96 feet per second. After how many seconds will the ball reach its maximum height? And, what is the maximum height?

12 Pair Share After Mrs. Dron got hit in the head with a pitch, Mr. Chester came up to bat. The equation h=-.004d 2 +.96d+3 represents the path the ball took after Mr. Chester hit the first pitch. How far off the ground was the ball when it was hit by the bat?

13 Answer h=-.004d 2 +.96d+3 h=-.004(0) +.96(0) + 3 h= 0 + 0 + 3 h= 3 feet, which is how far from the ground the ball was when it was hit by the bat

14 Homework Transformation Worksheet


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