Presentation on theme: "Chapter 2, Kinematics. Terminology Mechanics = Study of objects in motion. –2 parts to mechanics. Kinematics = Description of HOW objects move. –Chapters."— Presentation transcript:
Terminology Mechanics = Study of objects in motion. –2 parts to mechanics. Kinematics = Description of HOW objects move. –Chapters 2 & 4 (Ch. 3 is mostly math!) Dynamics = WHY objects move. –Introduction of the concept of FORCE. –Causes of motion, Newton’s Laws –Most of the course after Chapter 4 For a while, assume ideal point masses (no physical size). Later, extended objects with size.
Brief Overview of the Course Translational Motion = Straight line motion. –Chapters 2,4,5,9,13 Rotational Motion = Moving (rotating) in a circle. –Chapters 6,10,11,12 Oscillations = Moving (vibrating) back & forth in same path. –Chapter 15 Continuous Media Waves, Sound –Chapters 16,17,18 Fluids = Liquids & Gases –Chapter 14 Conservation Laws: Energy, Momentum, Angular Momentum –Just Newton’s Laws expressed in other forms! THE THEME OF THE COURSE IS NEWTON’S LAWS OF MOTION!!
Motion in One Dimension 1. Displacement: Sects. 1-4: Outline 2. Average velocity: 3. Instantaneous velocity: 4. Speed is the absolute value of the velocity 2. Time interval: 5. Average acceleration: 6. Instantaneous acceleration:
Reference Frames, Coordinate Systems & Displacement Every measurement must be made with respect to a reference frame. Usually, speed is relative to the Earth.
Coordinate Axes Define reference frame using a standard coordinate axes. 2 Dimensions (x,y) Note, if its convenient, could reverse + & - !
Coordinate Axes 3 Dimensions (x,y,z) Define direction using these.
Displacement & Distance Distance traveled by an object displacement of the object! Displacement = change in position of object. Displacement is a vector (magnitude & direction). Distance is a scalar (magnitude). Figure: distance = 100 m, displacement = 40 m East
Displacement x 1 = 10 m, x 2 = 30 m Displacement ∆x = x 2 - x 1 = 20 m ∆ Greek letter “delta” meaning “change in”
x 1 = 30 m, x 2 = 10 m Displacement ∆x = x 2 - x 1 = - 20 m Displacement is a VECTOR
Vectors and Scalars Many quantities in physics, like displacement, have a magnitude and a direction. Such quantities are called VECTORS. –Other quantities which are vectors: velocity, acceleration, force, momentum,... Many quantities in physics, like distance, have a magnitude only. Such quantities are called SCALARS. –Other quantities which are scalars: speed, temperature, mass, volume,...
The Text uses BOLD letters to denote vectors. I usually denote vectors with arrows over the symbol. In one dimension, we can drop the arrow and remember that a + sign means the vector points to right & a minus sign means the vector points to left.
Average Velocity Average Speed (Distance traveled)/(Time taken) Average Velocity (Displacement)/(Time taken) Velocity: Both magnitude & direction describing how fast an object is moving. A VECTOR. (Similar to displacement). Speed: Magnitude only describing how fast an object is moving. A SCALAR. (Similar to distance). Units: distance/time = m/s Scalar→ Vector→
Average Velocity, Average Speed Displacement from before. Walk for 70 s. Average Speed = (100 m)/(70 s) = 1.4 m/s Average velocity = (40 m)/(70 s) = 0.57 m/s
In general: ∆x = x 2 - x 1 = displacement ∆t = t 2 - t 1 = elapsed time Average Velocity: (∆x)/(∆t) = (x 2 - x 1 )/(t 2 - t 1 )
Example Person runs from x 1 = 50.0 m to x 2 = 30.5 m in ∆t = 3.0 s. ∆x = -19.5 m Average velocity = (∆x)/(∆t) = -(19.5 m)/(3.0 s) = -6.5 m/s. Negative sign indicates DIRECTION, (negative x direction)
Instantaneous velocity velocity at any instant of time average velocity over an infinitesimally short time Mathematically, instantaneous velocity: v = lim ∆t 0 [(∆x)/(∆t)] ≡ (dx/dt) lim ∆t 0 ratio (∆x)/(∆t) considered as a whole for smaller & smaller ∆t. As you should know, mathematicians call this a derivative. Instantaneous velocity v ≡ time derivative of displacement x
Acceleration Velocity can change with time. An object whose velocity is changing with time is said to be accelerating. Definition: Average acceleration = ratio of change in velocity to elapsed time. a (∆v)/(∆t) = (v 2 - v 1 )/(t 2 - t 1 ) –Acceleration is a vector. Instantaneous acceleration a = lim ∆t 0 [(∆v)/(∆t)] Units: velocity/time = distance/(time) 2 = m/s 2
Conceptual Question 1. Velocity & acceleration are both vectors. Are the velocity and the acceleration always in the same direction? NO!! If the object is slowing down, the acceleration vector is in the opposite direction of the velocity vector!
Deceleration “Deceleration”: A word meaning “slowing down”. We try to avoid using it in physics. Instead (in one dimen.) talk about positive & negative acceleration. This is because (for one dimen. motion) deceleration does not necessarily mean the acceleration is negative!
Conceptual Question 2. Velocity & acceleration are vectors. Is it possible for an object to have a zero acceleration and a non-zero velocity? YES!! If the object is moving at a constant velocity, the acceleration vector is zero!
Conceptual Question 3. Velocity & acceleration are vectors. Is it possible for an object to have a zero velocity and a non-zero acceleration? YES!! If the object is instantaneously at rest (v = 0) but is either on the verge of starting to move or is turning around & changing direction, the velocity is zero, but the acceleration is not!
Example 2.1: Calculating Average Velocity & Speed, p. 28 Problem: Use the figure & table to find the displacement & the average velocity of the car between positions (A) and (F).
Example 2.3: Average & Instantaneous Velocity, p. 25 Problem: A particle moves along the x axis. Its x coordinate varies with time as x = -4t + 2t 2. x is in meters & t is in seconds. The position-time graph for this motion is in the figure. a) Determine the displacement of the particle in the time intervals t = 0 to t = 1 s & t = 1 s to t = 3 s (A to B & B to C) b) Calculate the average velocity in the time intervals t = 0 to t = 1 s & t = 1 s to t = 3 s (A to B & B to C) c) Calculate the instantaneous velocity of the particle at t = 2.5 s (point C).
Example 2.4: Graphical Relationships between x, v x (v) & a x (a) Problem: The position of an object moving along the x axis varies with time as in the figure. Graph the velocity versus time and acceleration versus time curves for the object.
Example 2.5, Average & Instantaneous Acceleration, p. 30 Problem: The velocity of a particle moving along the x axis varies in time according to the expression v = (44 - 10t 2 ), where t is in seconds. a) Find the average acceleration in the time interval t = 0 to t = 2.0 s. b) Find the acceleration at t = 2.0 s.
Ch. 2, Sects. 1-4: Motion in One Dimension 1. Displacement: Summary 2. Average velocity: 3. Instantaneous velocity: 4. Speed is the absolute value of the velocity 2. Time interval: 5. Average acceleration: 6. Instantaneous acceleration: