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HISTOGRAMS Representing Data Module S1. Why use a Histogram When there is a lot of data When data is Continuous a mass, height, volume, time etc Presented.

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Presentation on theme: "HISTOGRAMS Representing Data Module S1. Why use a Histogram When there is a lot of data When data is Continuous a mass, height, volume, time etc Presented."— Presentation transcript:

1 HISTOGRAMS Representing Data Module S1

2 Why use a Histogram When there is a lot of data When data is Continuous a mass, height, volume, time etc Presented in a Grouped Frequency Distribution usually in groups or classes that are UNEQUAL

3 Continuous data NO GAPS between Bars

4 Bars are different in width Determined by Grouped Frequency Distribution

5 AREA is proportional to FREQUENCY NOT height, because of UNEQUAL classes! So we use FREQUENCY DENSITY = Frequency Class width

6 Grouped Frequency Distribution Time taken (nearest minute) Freq Speed, kph0< v 4040< v 5050< v 6060< v 9090< v 110 Frequency Classes No gaps GAPS!Need to adjust to Continuous Ready to graph

7 Adjusting Classes Class Widths Time taken (nearest minute) Freq ½4½19½29½39½59½

8 Frequency Density Time taken (nearest minute) Freq Class width Frequency Density

9 Drawing Sensible Scales Bases correctly aligned Plot the Class Boundaries Heights correct Frequency Density

10 Freq Dens Time (Mins)

11 Estimating a Frequency Imagine we want to Estimate the number of people with a time between 12 and 25 mins Because rounded to nearest minute Consider the interval 11.5 to 25.5

12 Freq Dens Time (Mins) Frequency = 0.9 x 8 = 7.2 Frequency = 1.8 x 6 = 10.8 Total Frequency = 18

13 …and the other one? Simpler to plot No adjustments required – class widths friendly No ½ values Estimation from the EXACT values given No adjustment required Estimate 15 to 56 would use 15 and 56! Appear LESS OFTEN in the exam Speed, kph0< v 4040< v 5050< v 6060< v 9090< v 110 Frequency


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