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Chapter 6.3: Enzyme Kinetics CHEM 7784 Biochemistry Professor Bensley.

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Presentation on theme: "Chapter 6.3: Enzyme Kinetics CHEM 7784 Biochemistry Professor Bensley."— Presentation transcript:

1 Chapter 6.3: Enzyme Kinetics CHEM 7784 Biochemistry Professor Bensley

2 CHAPTER 6.3 Enzyme Kinetics –description of enzyme kinetics by examining the Michaelis-Menten theory Today’s Objectives: (To learn and understand the)

3 What is (are?) Enzyme Kinetics? Kinetics is the study of the rate at which compounds react Rate of enzymatic reaction is affected by –Enzyme –Substrate –Effectors –Temperature

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5 How to Take Kinetic Measurements

6 Effect of Substrate Concentration Ideal Rate: Deviations due to: –Limitation of measurements –Substrate inhibition –Substrate prep contains inhibitors –Enzyme prep contains inhibitors

7 Plot V 0 vs. [S] Michaelis-Menten Equation Describes rectangular hyperbolic plot V o = Vmax [S] Km + [S]

8 K m = [S] @ ½ Vmax (units moles/L=M) (1/2 of enzyme bound to S) V max = velocity where all of the enzyme is bound to substrate (enzyme is saturated with S)

9 1)Measurements made to measure initial velocity (v o ). At v o very little product formed. Therefore, the rate at which E + P react to form ES is negligible and k -2 is 0. Therefore Initial Velocity Assumption E + S ESE + P k1k1 k -1 k2k2 E S + E S k -2 E+ P

10 Steady State Assumption E + S ESE + P k1k1 k -1 k2k2 Steady state Assumption = [ES] is constant. The rate of ES formation equals the rate of ES breakdown E S + E S E+ P

11 E + S ES k1k1 E S + E S Rate of ES formation Rate = k 1 [E] [S]

12 ESE + P k2k2 E S E+ P ESE + S k -1 E S + E S Rate of ES breakdown Rate = (k 2 [ES]) + (k -1 [ES]) Rate = [ES](k 2 + k -1 )

13 Therefore………if the rate of ES formation equals the rate of ES breakdown 1) k 1 [E][S] = [ES](k -1 + k 2 ) 2) (k -1 + k 2 ) / k 1 = [E][S] / [ES] 3) (k -1 + k 2 ) / k 1 = K m (Michaelis constant)

14 What does K m mean? 1.K m = [S] at ½ V max 2.K m is a combination of rate constants describing the formation and breakdown of the ES complex 3.K m is usually a little higher than the physiological [S]

15 What does K m mean? 4.K m represents the amount of substrate required to bind ½ of the available enzyme (binding constant of the enzyme for substrate) 5.K m can be used to evaluate the specificity of an enzyme for a substrate (if obeys M-M) 6.Small K m means tight binding; high K m means weak binding GlucoseKm = 8 X 10 -6 AlloseKm = 8 X 10 -3 MannoseKm = 5 X 10 -6 Hexokinase Glucose + ATP Glucose-6-P + ADP

16 What does k cat mean? E + S ES E + P k1k1 k -1 k cat

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18 What does k cat /K m mean?

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20 Aren’t Enzymes Kinetics Fun?! The final form of M-M equation in the case of a single substrate is k cat (turnover number): how many substrate molecules can one enzyme molecule convert per second K m (Michaelis constant): an approximate measure of substrate’s affinity for enzyme

21 Limitations of M-M 1.Some enzyme catalyzed rxns show more complex behaviorE + S ES EZ EP E + P With M-M can look only at rate limiting step 2.Often more than one substrate E+S 1 ES 1 +S 2 ES 1 S 2 EP 1 P 2 EP 2 +P 1 E+P 2 Must optimize one substrate then calculate kinetic parameters for the other 3.Assumes k -2 = 0 4.Assume steady state conditions

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24 V max Km K m ~ 1.3 mM V max ~ 0.25

25 -1/K m = -0.8 K m = 1.23 mM 1/V max = 4.0 V max = 0.25 1/


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