Download presentation

Presentation is loading. Please wait.

Published byJohn Murphy Modified over 3 years ago

1
BA A = turning point B = position of 3 rd wheel/trace, mid way along beam C= possible counterweight position, above 3 rd wheel/trace C 0.87m Beams 0.9t (left of pivot 0.31t right of pivot 0.6t) Plate+ brackets 0.45t Dee4 1.8t 2.55m 1.68m

2
Calculations for moments on H4 turntable with Dee4 ================================================== Dee4 moment = 2.8 m-tonnes beams on right moment = 0.504 m-tonnes Dee4 table on right moment = 0.63 m-tonnes Long beam (B) on left moment = 0.3795 m-tonnes Cross pieces to (B) on left moment = 0.1683 m-tonnes SM support on left moment = 0.317088 m-tonnes 2 diagonal beams on left moment = 0.143608 m-tonnes 2 vertical beams on left moment = 0.2013 m-tonnes Right 3.934 m-tonnes Left 1.2098 m-tonnes Difference 2.7242 m-tonnes on right Compensating weight on blue frame at (B) at 1.65m 1.651 tonnes

3
Inputs for calculations for moments on H4 turntable with Dee4 ================================================== macro moments * H4 turntable moments *Right of fulcrum A *=================== * Dee4 moment from fulcrum A at vertical screws * 2t load at 1.4m m1=1.4*2 message 'Dee4 moment = '//[m1]//' m-tonnes' *beams on right of fulcrum A *0.6t at average of 1.68/2 = 0.84m from fulcrum A m2=0.6*0.84 message 'beams on right moment = '//[m2]//' m-tonnes' *Dee4 table on right of fulcrum A *0.45t at average of 1.4m from fulcrum A m3=0.45*1.4 message 'Dee4 table on right moment = '//[m3]//' m-tonnes'

4
*Left of fulcrum A *=================== *Long beam at B, 0.23t at 1.65m from fulcrum A m4=0.23*1.65 message 'Long beam (B) on left moment = '//[m4]//' m-tonnes' *Cross pieces to (B) 0.204t at 0.825m m5=0.204*0.825 message 'Cross pieces to (B) on left moment = '//[m5]//' m-tonnes *SM support table 0.334t (334kg) underframe, 0.4t top frame? at 865/2cm = 0.432m m6=0.734*0.432 message 'SM support on left moment = '//[m6]//' m-tonnes' *Diagonal beams, each 0.058 tonnes at 0.825+0.413 = 1.238m m7=0.058*2*1.238 message '2 diagonal beams on left moment = '//[m7]//' m-tonnes' *Vertical beams, each 0.061 tonnes at 1.65m m8=0.061*2*1.65 message '2 vertical beams on left moment = '//[m8]//' m-tonnes'

5
*Totals *====== r=[m1]+[m2]+[m3] l=[m4]+[m5]+[m6]+[m7]+[m8] message 'Right '//[r]//' m-tonnes' message 'Left '//[l]//' m-tonnes' diff=[r]-[l] message 'Difference '//[diff]//' m-tonnes on right' * get balancing needed weight * X tonnes * 1.65m = [diff] * X tonnes = [diff]/1.65 X=[diff]/1.65 Message 'Compensating weight on blue frame at (B) at 1.65m '//[X]//' tonnes'

Similar presentations

OK

Chapter 8 Review. 1. How is torque calculated? T = F x l.

Chapter 8 Review. 1. How is torque calculated? T = F x l.

© 2017 SlidePlayer.com Inc.

All rights reserved.

Ads by Google

Ppt on hotel industry in india 2012 Ppt on as 14 amalgamation synonyms Download ppt on political parties class 10 Ppt on swami vivekananda speech Ppt on power sharing in democracy the will of the majority Ppt on content addressable memory Ppt on computer tips and tricks The heart anatomy and physiology ppt on cells Ppt online shopping project proposal Download ppt on teamviewer