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Welcome to Interactive Chalkboard Glencoe Geometry Interactive Chalkboard Copyright © by The McGraw-Hill Companies, Inc. Developed by FSCreations, Inc.,

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Presentation on theme: "Welcome to Interactive Chalkboard Glencoe Geometry Interactive Chalkboard Copyright © by The McGraw-Hill Companies, Inc. Developed by FSCreations, Inc.,"— Presentation transcript:

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2 Welcome to Interactive Chalkboard Glencoe Geometry Interactive Chalkboard Copyright © by The McGraw-Hill Companies, Inc. Developed by FSCreations, Inc., Cincinnati, Ohio 45202 Send all inquiries to: GLENCOE DIVISION Glencoe/McGraw-Hill 8787 Orion Place Columbus, Ohio 43240

3 Splash Screen

4 Transparency 7 Click the mouse button or press the Space Bar to display the answers.

5 Transparency 7a

6 Contents Lesson 2-1Inductive Reasoning and Conjecture Lesson 2-2Logic Lesson 2-3Conditional Statements Lesson 2-4Deductive Reasoning Lesson 2-5Postulates and Paragraph Proofs Lesson 2-6Algebraic Proof Lesson 2-7Proving Segment Relationships Lesson 2-8Proving Angle Relationships

7 Lesson 7 Contents Example 1Proof With Segment Addition OBJECTIVE: To write proofs involving segment addition (2.9.8J) (M8.D.1.1)

8 Key Concept: POSTULATE 2.8 – Ruler Postulate The points on any line or line segment can be paired with real numbers so that, given any 2 points A and B on a line, A corresponds to zero, and B corresponds to a positive real number.

9 Key Concept: POSTULATE 2.9: Segment Addition Postulate. If B is between A and C, then AB + BC = AC. If AB + BC = AC, then B is between A and C.

10 Example 7-1a Given: PR = QS Prove the following. Prove: PQ = RS 1. Given PR = QS 1. 2. Subtraction Property PR – QR = QS – QR 2. 3. Segment Addition Postulate PR – QR = PQ; QS – QR = RS 3. 4. Substitution PQ = RS 4. Proof: Statements Reasons

11 Example 7-1b Prove the following. Prove: Given:

12 Example 7-1c Proof: Statements Reasons 1. Given 2. Transitive Property 3. Given 4. Addition Property AC = AB, AB = BX AC = BX CY = XD AC + CY = BX + XD 5. Segment Addition Property AC + CY = AY; BX + XD = BD AY = BD 6. Substitution 1. 2. 3. 4. 5. 6.

13 REVIEW Justify with a property: 1.If AB = AC + CB, then AB – AC = CB 2.If m  P + m  Q = 110 and m  R = 110, then m  P + m  Q = m  R. 3.If x(y + z) = a, then xy + xz = a. 4.If n –17 = 39, then n = 56. 5.If cv = md and md = 15, then cv = 15. Subtraction Substitution Dist. Prop. Add. Prop. Trans. Prop.

14 End of Lesson 7

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