1. Scientific Notation Converting into Sci. Notation: Converting into Sci. Notation:  Move decimal until there’s 1 digit to its left. Places moved = exponent.  Large # (>1)  positive exponent Small # ( 1)  positive exponent Small # (<1)  negative exponent 65,000 kg  6.5 × 10 4 kg

2. Scientific Notation 7. 2,400,000  g 8. 0.00256 kg 9.7  10 -5 km 10.6.2  10 4 mm Practice Problems 2.4  10 6  g 2.56  10 -3 kg 0.00007 km 62,000 mm

3. Scientific Notation Calculating with Sci. Notation Calculating with Sci. Notation (5.44 × 10 7 g) ÷ (8.1 × 10 4 mol) = 5.44 EXP EE ÷ ÷ EXP EE ENTER EXE 78.1 4 = 671.6049383= 670 g/mol= 6.7 × 10 2 g/mol Type on your calculator:

4. Practice 1) 5.21 x 10 4 + 6.7 x 10 3 = 1) 5.21 x 10 4 + 6.7 x 10 3 = 5.9 x 10 4 5.9 x 10 4 2) 9.55 x 10 14 / 3.354 x 10 6 = 2) 9.55 x 10 14 / 3.354 x 10 6 = 2.85 x 10 8 2.85 x 10 8 3) 8.467 x 10 5 x 2.01 x 10 8 = 3) 8.467 x 10 5 x 2.01 x 10 8 = 1.70 x 10 14 1.70 x 10 14 4) 7.668 x 10 7 – 3.4 x 10 8 = 4) 7.668 x 10 7 – 3.4 x 10 8 = -2.63 x 10 8 -2.63 x 10 8

5. Density Density = mass per unit volume Density = mass per unit volume Units for density: g/cm 3 or g/mL or g/L Units for density: g/cm 3 or g/mL or g/L (solids) (liquids) (gas) (solids) (liquids) (gas) D = MVMV

6. Density An object has a volume of 825 cm 3 and a density of 13.6 g/cm 3. Find its mass. An object has a volume of 825 cm 3 and a density of 13.6 g/cm 3. Find its mass. GIVEN: V = 825 cm 3 D = 13.6 g/cm 3 M = ? WORK : M = DV M = (13.6 g/cm 3 )(825cm 3 ) M = 11,200 g

7. Density A liquid has a density of 0.87 g/mL. What volume is occupied by 25 g of the liquid? A liquid has a density of 0.87 g/mL. What volume is occupied by 25 g of the liquid? GIVEN: D = 0.87 g/mL V = ? M = 25 g WORK : V = M D V = 25 g 0.87 g/mL V = 29 mL

8. Dimensional Analysis The “Factor-Label” Method The “Factor-Label” Method  Units, or “labels” are canceled, or “factored” out

9. Dimensional Analysis Steps: Steps: 1. Identify starting & ending units. 2. Line up conversion factors so units cancel. 3. Multiply all top numbers & divide by each bottom number. 4. Check units & answer.

10. Dimensional Analysis 5) Your European hairdresser wants to cut your hair 8.0 cm shorter. How many inches will he be cutting off? 8.0 cm 1 in 2.54 cm = 3.1 in cmin

11. Dimensional Analysis How many milliliters are in 1.00 quart of milk? How many milliliters are in 1.00 quart of milk? 1.00 qt 1 L 1.06 qt = 943 mL qtmL 1000 mL 1 L 

12. Dimensional Analysis 6) Taft football needs 550 cm for a 1st down. How many yards is this? 550 cm 1 in 2.54 cm = 6.0 yd cmyd 1 ft 12 in 1 yd 3 ft

13. Dimensional Analysis You have 1.5 pounds of gold. Find its volume in cm 3 if the density of gold is 19.3 g/cm 3. You have 1.5 pounds of gold. Find its volume in cm 3 if the density of gold is 19.3 g/cm 3. lbcm 3 1.5 lb 1 kg 2.2 lb = 35 cm 3 1000 g 1 kg 1 cm 3 19.3 g

14. Dimensional Analysis Convert 75.0 in 3 to cm 3 Convert 75.0 in 3 to cm 3 2.54 cm = 1 in, so 16.387064 cm 3 = 1 in 3 2.54 cm = 1 in, so 16.387064 cm 3 = 1 in 3 75.0 in 3 16.387064 cm 3 1 in 3 = 1230 cm 3

15. Dimensional Analysis Convert 35.0 mi/hr to m/min Convert 35.0 mi/hr to m/min  (1609 m = 1 mile) 35.0mi = 35.0mi = 1 hr 1 mi 1609 m 60 min 1 hr 939 m/min