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Published byLeslie Paul Modified over 8 years ago

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Dependent Probability

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P(Yellow then Blue) = P (Pink then not blue) = P(Yellow then Yellow) = 3 32 == = 2 8 3 8 1 4 3 8 2 8 2 8 1 4 1 4 0 8 5 8 0 64 1 16 = = With Replacing 0 =

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P(Yellow then Blue) = P (Purple then Purple) = P(Yellow then Yellow) = 3 28 == = 2 8 3 7 1 4 3 7 2 8 1 7 1 4 1 7 1 8 0 7 0 56 1 28 = = With Out Replacing 0 =

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Mary is getting ready to paint her bedroom. Her mother went to the store and purchased samples for her to choose from. Colors# of samples Red shades2 Orange Shades4 Yellow Shades1 Green Shades2 Blue Shades4 Purple Shades3 If she randomly picks a color sample then does not replace it and picks another color sample, then what is the probability of Mary choosing …… A red shade and then a purple shade? A blue shade and then a orange shade? A yellow shade and then a yellow shade? 2 16 3 15 4 16 4 15 1 16 0 15 1 8 1 5 1 4 4 15 = = 1 40 = = 0 = 1 1 1 15

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P( then ) = == = = = With Out Replacing =

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Mary is getting ready to paint her bedroom. Her mother went to the store and purchased samples for her to choose from. Colors# of samples Red shades2 Orange Shades4 Yellow Shades1 Green Shades2 Blue Shades4 Purple Shades3 If she randomly picks a color sample then does not replace it and picks another color sample, then what is the probability of Mary choosing …… A red shade and then a purple shade? A blue shade and then a orange shade? A yellow shade and then a yellow shade? = = = = =

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