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1 Chapter 4 Compounds and Their Bonds 4.1 Octet Rule and Ions Copyright © 2005 by Pearson Education, Inc. Publishing as Benjamin Cummings.

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Presentation on theme: "1 Chapter 4 Compounds and Their Bonds 4.1 Octet Rule and Ions Copyright © 2005 by Pearson Education, Inc. Publishing as Benjamin Cummings."— Presentation transcript:

1 1 Chapter 4 Compounds and Their Bonds 4.1 Octet Rule and Ions Copyright © 2005 by Pearson Education, Inc. Publishing as Benjamin Cummings

2 2 Learning Goals Using the octet rule, write the symbols of the simple ions for the representative elements. Using charge balance, write the correct formula for an ionic compound. Given the formula of an ionic compound, write the correct name; given the name of an ionic compound, write the correct formula. Write the name and formula of a compound containing a polyatomic ion. Given the formula of a covalent compound, write its correct name; given the name of a covalent compound, write its formula. Use electronegativity to determine the polarity of a bond. Predict the three-dimensional structure of a molecule and classify it as polar or nonpolar.

3 3 An octet is 8 valence electrons. is associated with the stability of the noble gases. He is stable with 2 valence electrons (duet). valence electrons He 2 2 Ne 2, 8 8 Ar 2, 8, 8 8 Kr 2, 8, 14, 8 8 Octet Rule

4 4 Ionic and Covalent Bonds Atoms form octets to become more stable. by losing, gaining, or sharing valence electrons. by forming ionic bonds or covalent bonds. Copyright © 2005 by Pearson Education, Inc. Publishing as Benjamin Cummings

5 5 Metals Form Positive Ions Metals form positive ions by a loss of their valence electrons. with the electron configuration of the nearest noble gas. that have fewer electrons than protons. Group 1A metals  ion 1+ Group 2A metals  ion 2+ Group 3A metals  ion 3+ Copyright © 2005 by Pearson Education, Inc. Publishing as Benjamin Cummings

6 6 Formation of a Sodium Ion, Na + Sodium achieves an octet by losing its one valence electron. Copyright © 2005 by Pearson Education, Inc. Publishing as Benjamin Cummings 2, 8, 12, 8

7 7 Charge of Sodium Ion, Na + With the loss of its valence electron, the sodium ion has a +1 charge. Sodium atom Sodium ion 11p + 11e - 10e - 0 1+ Copyright © 2005 by Pearson Education, Inc. Publishing as Benjamin Cummings 2, 8

8 8 Formation of Mg 2+ Magnesium achieves an octet by losing its two valence electrons. 2, 8, 22, 8 Copyright © 2005 by Pearson Education, Inc. Publishing as Benjamin Cummings

9 9 Charge of Magnesium Ion Mg 2+ With the loss of two valence Electrons, magnesium forms a positive ion with a +2 charge. Mg atomMg 2+ ion 12p + 12p + 12e- 10e - 0 2+ Copyright © 2005 by Pearson Education, Inc. Publishing as Benjamin Cummings

10 10 Learning Check A. The number of valence electrons in aluminum is 1) 1e -. 2) 2e -.3) 3e -. B. The change in electrons for octet requires a 1) loss of 3e -. 2) gain of 3e -. 3) a gain of 5e -. C. The ionic charge of aluminum is 1) 3-.2) 5-.3) 3 +. D. The symbol for the aluminum ion is 1) Al 3+.2) Al 3-.3) Al +.

11 11 Solution A. The number of valence electrons in aluminum is 3) 3 e -. B. The change in electrons for octet requires a 1) loss of 3e -. C. The ionic charge of aluminum is 3) 3 +. D. The symbol for the aluminum ion is 1) Al 3+.

12 12 Formation of Negative Ions In ionic compounds, nonmetals achieve an octet arrangement. gain electrons. form negatively charged ions with 3-, 2-, or 1- charges.

13 13 Formation of a Chloride, Cl - Chlorine achieves an octet by adding an electron to its valence electrons. 2, 8, 72, 8, 8 Copyright © 2005 by Pearson Education, Inc. Publishing as Benjamin Cummings

14 14 Charge of a Chloride Ion, Cl - By gaining one electron, the chloride ion has a -1 charge. Chlorine atom Chloride ion 17p + 17p + 17e - 18e - 0 1 – Copyright © 2005 by Pearson Education, Inc. Publishing as Benjamin Cummings

15 15 Ionic Charge from Group Numbers The charge of a positive ion is equal to its Group number. Group 1A(1) = 1+ Group 2A(2) = 2+ Group 3A(3) = 3+ The charge of a negative ion is obtained by subtracting 8 or 18 from its Group number. Group 6A(16) = 6 - 8 = 2- or 16 - 18= 2-

16 16 Some Ionic Charges I-I- Copyright © 2005 by Pearson Education, Inc. Publishing as Benjamin Cummings

17 17 A. The number of valence electrons in sulfur is 1) 4e -. 2) 6e -. 3) 8e -. B. The change in electrons for octet requires a 1) loss of 2e -. 2) gain of 2e -. 3) a gain of 4e -. C. The ionic charge of sulfur is 1) 2+. 2) 2-. 3) 4-. Learning Check

18 18 A. The number of valence electrons in sulfur is 2) 6e -. B. The change in electrons for octet requires a 2) gain of 2e -. C. The ionic charge of sulfur is 2) 2-. Solution


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