# 27.04.05 LO: To solve word problems involving numbers and quantities based on measures.

## Presentation on theme: "27.04.05 LO: To solve word problems involving numbers and quantities based on measures."— Presentation transcript:

27.04.05 LO: To solve word problems involving numbers and quantities based on measures.

What unit could we use to measure long distances?

1km is slightly more than ½ mile. 1 mile0

1km is slightly more than ½ mile. 1 mile0

1km is slightly more than ½ mile. 8km is approximately 5 miles 0 0 8km 5 miles

1km is slightly more than ½ mile. 8km is approximately 5 miles What is the relationship between 1 mile and 1km? 1 mile =………km1 km = ……miles

1 mile =………km1 km = ……miles

0 0 8km 5 miles 1 mile =………km1 km = ……miles

0 0 8km 5 miles 1 mile =1 km = 8 5 km 5 8 km

0 0 5 miles 1 mile =1 km = 8 5 km 5 8 km …but how do we convert these to decimals?

1 mile = 1.6 km 1km = 0.625miles

Task Place Distance from school: In milesIn km Dogsthorpe (Miss Robson) 5 miles Whittlesey (Mr Morris) 4 miles Lutton (Miss Ryan) 18.3km Bourne (Mrs Cotton) 32.7km Farcet (Miss Fletcher) 2 miles 1 mile = 1.6 km1km = 0.625 miles

Task Place Distance from school: In milesIn km Dogsthorpe (Miss Robson) 5 miles8 km Whittlesey (Mr Morris) 4 miles6.4km Lutton (Miss Ryan) 11.4375 miles18.3km Bourne (Mrs Cotton) 20.4375 miles32.7km Farcet (Miss Fletcher) 2 miles3.2 km 1 mile = 1.6 km1km = 0.625 miles

Extension A Can of cola is about 10 cm high. If the cans were laid end to end, how many cans would be needed to cover a distance of 1 mile?

1 can = 10cm 10 cans = 1m 10,000 = 1km 10,000 x 1.6 = ????????????

1 can = 10cm 10 cans = 1m 10,000 = 1km 10,000 x 1.6 = 16,000 miles

What have we learned? LO: To solve word problems involving numbers and quantities based on measures.

Download ppt "27.04.05 LO: To solve word problems involving numbers and quantities based on measures."

Similar presentations