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27.04.05 LO: To solve word problems involving numbers and quantities based on measures.

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Presentation on theme: "27.04.05 LO: To solve word problems involving numbers and quantities based on measures."— Presentation transcript:

1 LO: To solve word problems involving numbers and quantities based on measures.

2 What unit could we use to measure long distances?

3

4 1km is slightly more than ½ mile. 1 mile0

5 1km is slightly more than ½ mile. 1 mile0

6 1km is slightly more than ½ mile. 8km is approximately 5 miles 0 0 8km 5 miles

7 1km is slightly more than ½ mile. 8km is approximately 5 miles What is the relationship between 1 mile and 1km? 1 mile =………km1 km = ……miles

8 1 mile =………km1 km = ……miles

9 0 0 8km 5 miles 1 mile =………km1 km = ……miles

10 0 0 8km 5 miles 1 mile =1 km = 8 5 km 5 8 km

11 0 0 5 miles 1 mile =1 km = 8 5 km 5 8 km …but how do we convert these to decimals?

12

13

14 1 mile = 1.6 km 1km = 0.625miles

15 Task Place Distance from school: In milesIn km Dogsthorpe (Miss Robson) 5 miles Whittlesey (Mr Morris) 4 miles Lutton (Miss Ryan) 18.3km Bourne (Mrs Cotton) 32.7km Farcet (Miss Fletcher) 2 miles 1 mile = 1.6 km1km = miles

16 Task Place Distance from school: In milesIn km Dogsthorpe (Miss Robson) 5 miles8 km Whittlesey (Mr Morris) 4 miles6.4km Lutton (Miss Ryan) miles18.3km Bourne (Mrs Cotton) miles32.7km Farcet (Miss Fletcher) 2 miles3.2 km 1 mile = 1.6 km1km = miles

17 Extension A Can of cola is about 10 cm high. If the cans were laid end to end, how many cans would be needed to cover a distance of 1 mile?

18 1 can = 10cm 10 cans = 1m 10,000 = 1km 10,000 x 1.6 = ????????????

19 1 can = 10cm 10 cans = 1m 10,000 = 1km 10,000 x 1.6 = 16,000 miles

20 What have we learned? LO: To solve word problems involving numbers and quantities based on measures.


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