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9-8 Surface Area of Pyramids and Cones Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day Lesson Quizzes Lesson.

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Presentation on theme: "9-8 Surface Area of Pyramids and Cones Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day Lesson Quizzes Lesson."— Presentation transcript:

1 9-8 Surface Area of Pyramids and Cones Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day Lesson Quizzes Lesson Quizzes

2 9-8 Surface Area of Pyramids and Cones Warm Up 1. A rectangular prism is 0.6 m by 0.4 m by 1.0 m. What is the surface area? 2. A cylindrical can has a diameter of 14 cm and a height of 20 cm. What is the surface area to the nearest tenth? Use 3.14 for . 2.48 m 2 1186.9 cm 2

3 9-8 Surface Area of Pyramids and Cones Problem of the Day Sandy is building a model of a pyramid with a hexagonal base. If she uses a toothpick for each edge, how many toothpicks will she need? 12

4 9-8 Surface Area of Pyramids and Cones Prep for MA.8.G.5.1 …Convert units of measure between different measurement systems…and dimensions including…area…and derived units to solve problems. Rev MA.7.G.2.1 Sunshine State Standards

5 9-8 Surface Area of Pyramids and Cones Vocabulary slant height regular pyramid right cone

6 9-8 Surface Area of Pyramids and Cones The slant height of a pyramid or cone is measured along its lateral surface. In a right cone, a line perpendicular to the base through the tip of the cone passes through the center of the base. The base of a regular pyramid is a regular polygon, and the lateral faces are all congruent. Right cone Regular Pyramid

7 9-8 Surface Area of Pyramids and Cones

8 9-8 Surface Area of Pyramids and Cones Additional Example 1: Finding Surface Area Find the surface area of each figure to the nearest tenth. Use 3.14 for .  20.2 ft 2 A. S = B + Pl 1212 = (2.4 2.4) + (9.6)(3) 1212

9 9-8 Surface Area of Pyramids and Cones Check It Out: Example 1 = (3 3) + (12)(5) 1212 B. S = r 2 + rl = 39 m 2 = (7 2 ) + (7)(18) = 175  549.5 ft 2 5 m 3 m 7 ft 18 ft A. S = B + Pl 1212 Find the surface area of each figure to the nearest tenth. Use 3.14 for .

10 9-8 Surface Area of Pyramids and Cones Additional Example 2: Exploring the Effects of Changing Dimensions A cone has diameter 8 in. and slant height 3 in. Explain whether tripling the slant height would have the same effect on the surface area as tripling the radius. They would not have the same effect. Tripling the radius would increase the surface area more than tripling the slant height.

11 9-8 Surface Area of Pyramids and Cones Check It Out: Example 2 Original DimensionsTriple the Slant Height Triple the Radius S = r 2 + rl = (4.5) 2 + (4.5)(2) = 29.25in 2  91.8 in 2 S = r 2 + r(3l) = (4.5) 2 + (4.5)(6) = 47.25in 2  148.4 in 2 S = r) 2 + r)l = (13.5) 2 + (13.5)(2) = 209.25in 2  657.0 in 2 A cone has diameter 9 in. and a slant height 2 in. Explain whether tripling the slant height would have the same effect on the surface area as tripling the radius. They would not have the same effect. Tripling the radius would increase the surface area more than tripling the height.

12 9-8 Surface Area of Pyramids and Cones Additional Example 3: Application The upper portion of an hourglass is approximately an inverted cone with the given dimensions. What is the lateral surface area of the upper portion of the hourglass? = (10)(26)  816.8 mm 2 Pythagorean Theorem Lateral surface area L = rl a 2 + b 2 = l 2 10 2 + 24 2 = l 2 l = 26 24 mm

13 9-8 Surface Area of Pyramids and Cones Check It Out: Example 3 A large road construction cone is almost a full cone. With the given dimensions, what is the lateral surface area of the cone? = (9)(15)  424.1 in 2 12 in. 9 in. Pythagorean Theorem a 2 + b 2 = l 2 9 2 + 12 2 = l 2 l = 15 Lateral surface area L = rl

14 9-8 Surface Area of Pyramids and Cones Standard Lesson Quiz Lesson Quizzes Lesson Quiz for Student Response Systems

15 9-8 Surface Area of Pyramids and Cones Lesson Quiz: Part I Find the surface area of each figure to the nearest tenth. Use 3.14 for . 1. the triangular pyramid 2. the cone 175.8 in 2 6.2 m 2

16 9-8 Surface Area of Pyramids and Cones 3. Tell whether doubling the dimensions of a cone will double the surface area. Lesson Quiz: Part II It will more than double the surface area because you square the radius to find the area of the base.

17 9-8 Surface Area of Pyramids and Cones 1. Identify the surface area of the triangular pyramid to the nearest tenth. A. 15.1 m 2 B. 26.2 m 2 C. 30.3 m 2 D. 42.3 m 2 Lesson Quiz for Student Response Systems

18 9-8 Surface Area of Pyramids and Cones 2. Identify the surface area of the cone to the nearest tenth. A. 146.4 in 2 B. 141.8 in 2 C. 135.8 in 2 D. 131.9 in 2 Lesson Quiz for Student Response Systems

19 9-8 Surface Area of Pyramids and Cones 3. Tell whether tripling the dimensions of the cone will triple the surface area. A. It will be more than triple the area because you square the radius to find the area of the base. B. It will be more than triple the area because you triple the radius to find the area of the base. C. It will be less than triple the area because you triple the radius to find the area of the base. D. It will be less than triple the area because you square the radius to find the area of the base Lesson Quiz for Student Response Systems


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