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Stoichiometry. Definition: – The proportional relationship between two or more substances during a chemical reaction – Based on one amount of a substance.

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Presentation on theme: "Stoichiometry. Definition: – The proportional relationship between two or more substances during a chemical reaction – Based on one amount of a substance."— Presentation transcript:

1 Stoichiometry

2 Definition: – The proportional relationship between two or more substances during a chemical reaction – Based on one amount of a substance in a chemical equation, you will be able to calculate the amount of any other substance in a reaction.

3 Volume Mass MOLES Atoms MOLES Mass Atoms Volume Substance A (Have) Substance B (Looking For) Density Molar Mass Avogadros Number Molar Mass Density Avogadros Number Balanced Chemical Equation 22.4 L/mol at STP

4 Problems Involving Mass What mass of NH 3 can be made from 1221g H 2 and excess N 2 ? N 2 + 3H 2 2NH 3 – First, write what you know Mass of H 2 = 1221g H 2 Molar Mass of H 2 = 2.02 g/mol (this can not be your limiting significant figure) Mass of NH 3 = ?g NH 3 Molar Mass of NH 3 = 17.04 g/mol

5 Write your mathematical equation Start with what you were given 1221g H 2 Cancel units 1 mol H 2 2.02 g H 2 Use the balanced chemical equation 2 mol NH 3 3 mol H 2 17.04 g NH 3 1 mol NH 3 X XX = 6867 g NH 3

6 Problems Involving Particles (Atoms) How many grams of C 5 H 8 form from 1.89x 10 24 molecules of C 5 H 12 ? (Answer is 214g C 5 H 8 ) C 5 H 12 (l) C 5 H 8 (l) + 2H 2 (g) – Write what you know Atoms of C 5 H 12 = 1.89x 10 24 molecules Avogadros Number = 6.022x 10 23 molecules/mol Molar Mass of C 5 H 8 = 68.13 g/mol Mass of C 5 H 8 = ? g

7 Write your mathematical equation Start with what you were given Cancel unitsUse the balanced chemical equation 1.89x 10 24 molecules C 5 H 12 1 mol C 5 H 12 6.022x 10 23 molecules C 5 H 12 1 mol C 5 H 8 1 mol C 5 H 12 68.13 g C 5 H 8 1 mol C 5 H 8 X X X 214 g C 5 H 8

8 Problems Involving Volume What volume of H 3 PO 4 forms when 56mL POCl 3 completely react? (density of POCl 3 = 1.67 g/mL; density of H 3 PO 4 = 1.83 g/mL) POCl 3 (l) + 3H 2 O (l) H 3 PO 4 (l) + 3HCl (g) –W–Write what you know Volume POCl 3 = 56mL POCl 3 Density of POCl 3 = 1.67 g/mL Molar Mass of POCl 3 = 153.32 g/mol Molar Mass of H 3 PO 4 = 98.00 g/mol Density of H 3 PO 4 = 1.83 g/mL Volume of H 3 PO 4 = ? mL

9 Write your mathematical equation Start with what you were given 56 mL POCl 3 1.67 g POCl 3 1 mL POCl 3 1 mol POCl 3 153.32 g POCl 3 1 mol H 3 PO 4 1 mol POCl 3 98.00 g H 3 PO 4 1 mol H 3 PO 4 1 mL H 3 PO 4 1.83 g H 3 PO 4 XXXXX Cancel unitsUse the balanced chemical equation = 33mL H 3 PO 4


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