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Boyle’s Law - Review P1V1 = P2V2

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**Pressure can be in any units Volume can be in any units**

Boyle’s Law P1V1 = P2V2 Pressure can be in any units Volume can be in any units

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**Charles’ Law If temperature increases, volume increases**

If temperature decreases, volume decreases This is direct variation (compared to inverse for Boyle’s law)

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**Charles Law Volume can be in any units Temperature must be in Kelvin**

V1 = V2 T1 T2 Volume can be in any units Temperature must be in Kelvin To convert Celsius to Kelvin, add 273 (K = C )

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**Charles law For example:**

The temperature inside my fridge is 4 C. If I place a balloon in my fridge that initially has a temperature of 22 C and a volume of .5 L, what will be the volume of the balloon when it is fully cooled by my refrigerator?

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**Charles’ Law First convert temperatures to Kelvin 4 + 273 = 277K**

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Charles’ Law Make a list of what you know V1 = T1 = V2 = T2 =

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Charles’ Law V1 = .5 L T1 = V2 = T2 =

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Charles’ Law V1 = .5 L T1 = 295K V2 = T2 =

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Charles’ Law V1 = .5 L T1 = 295K V2 = x T2 =

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Charles’ Law V1 = .5 L T1 = 295K V2 = x T2 = 277K

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**Charles’ Law Put the information into the equation: V1 = V2 T1 T2**

.5 = x

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**Charles’ Law Cross multiply to solve for x .5(277) = x(295)**

x = .47 Liters

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**Charles’ Law For Example:**

A man heats a balloon in the oven. If the balloon initially has a volume of 0.4 L and a temperature of 20 C, what will the volume of the balloon be after he heats it to a temperature of 250 C?

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**Charles’ Law Convert temperatures to Kelvin 20 + 273 = 293 K**

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Charles’ Law Make a list of what you know V1 = T1 = V2 = T2 =

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**Charles’ law Make a list of what you know V1 = .4 L T1 = 293 K V2 = x**

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**Charles’ law Put the information into the equation: V1 = V2 T1 T2**

.4 = x

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**Charles’ law Cross multiply to solve for x .4(523) = x(293)**

x = .71 L

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