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Boyles Law - Review P 1 V 1 = P 2 V 2. Boyles Law P 1 V 1 = P 2 V 2 Pressure can be in any units Volume can be in any units.

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Presentation on theme: "Boyles Law - Review P 1 V 1 = P 2 V 2. Boyles Law P 1 V 1 = P 2 V 2 Pressure can be in any units Volume can be in any units."— Presentation transcript:

1 Boyles Law - Review P 1 V 1 = P 2 V 2

2 Boyles Law P 1 V 1 = P 2 V 2 Pressure can be in any units Volume can be in any units

3 Charles Law If temperature increases, volume increases If temperature decreases, volume decreases This is direct variation (compared to inverse for Boyles law)

4 Charles Law V 1 = V 2 T 1 T 2 T 1 T 2 Volume can be in any units Temperature must be in Kelvin To convert Celsius to Kelvin, add 273 (K = C )

5 Charles law For example: The temperature inside my fridge is 4 C. If I place a balloon in my fridge that initially has a temperature of 22 C and a volume of.5 L, what will be the volume of the balloon when it is fully cooled by my refrigerator?

6 Charles Law First convert temperatures to Kelvin = 277K = 295K

7 Charles Law Make a list of what you know V 1 = T 1 = V 2 = T 2 =

8 Charles Law V 1 =.5 L T 1 = V 2 = T 2 =

9 Charles Law V 1 =.5 L T 1 = 295K V 2 = T 2 =

10 Charles Law V 1 =.5 L T 1 = 295K V 2 = x T 2 =

11 Charles Law V 1 =.5 L T 1 = 295K V 2 = x T 2 = 277K

12 Charles Law Put the information into the equation: V 1 = V 2 T 1 T 2 T 1 T 2.5 = x

13 Charles Law Cross multiply to solve for x.5(277) = x(295) = 295x x =.47 Liters

14 Charles Law For Example: A man heats a balloon in the oven. If the balloon initially has a volume of 0.4 L and a temperature of 20 C, what will the volume of the balloon be after he heats it to a temperature of 250 C?

15 Charles Law Convert temperatures to Kelvin = 293 K = 523 K

16 Charles Law Make a list of what you know V 1 = T 1 = V 2 = T 2 =

17 Charles law Make a list of what you know V 1 =.4 L T 1 = 293 K V 2 = x T 2 = 523 K

18 Charles law Put the information into the equation: V 1 = V 2 T 1 T 2 T 1 T 2.4 = x

19 Charles law Cross multiply to solve for x.4(523) = x(293) = 293x x =.71 L


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