Download presentation

Presentation is loading. Please wait.

Published byWyatt Ritchie Modified over 4 years ago

1
**Chapter 11 and supplemental Ms. Lockhart Chemistry**

Stoichiometry Chapter 11 and supplemental Ms. Lockhart Chemistry

2
**Stoichiometry Importance**

By understanding the mole we can use the information to Predict mass or volume of a product. Predict how much reactant is needed for a reaction. Make substances of all kinds like Your sneakers Glue Your clothes Gum Candy Petrochemicals (oils, vaseline, gas)

3
**Other uses % by mass (% composition) Empirical Formula**

Formula of a Hydrate Stoichiometric calculations Limiting Reagent % yield

4
Stoichiometry You can interpret a lot from a balanced chemical reaction. Iron is added to oxygen gas (O2) to yield iron (III) oxide (ferric oxide). 4 Fe O2 2Fe2O3 Atoms Moles Mass Total mass

5
Stoichiometry Nitrogen gas (N2) is added to hydrogen gas (H2) to make ammonia (NH3). N H2 NH3 Atoms Moles Mass Total mass

6
**Practice Stoichiometry**

3.00 g Magnesium (Mg) is heated with excess oxygen gas (O2) to make magnesium oxide. 2 Mg O2 MgO

7
**Steps to Stoichiometry**

Copy the word equation (write the chemical reaction in words). Write the word equation into a formula equation. Balance the chemical reaction. 2 Mg O2 MgO

8
**Steps to Stoichiometry**

Write given information under the balanced chemical reaction 2 Mg O2 MgO 3.00 g

9
**Steps to Stoichiometry**

Write what you are looking for. 2 Mg O2 MgO 3.00 g ? O2

10
**Steps to Stoichiometry**

Convert given information into moles. 2 Mg O2 MgO 3.00 g ? O2 3.00 g Mg x 2 moles Mg = 3x2/24.31 = moles Mg 24.31 g Mg

11
**Steps to Stoichiometry**

Use mole ratio to get moles to the correct representative particles. 2 Mg O2 MgO 3.00 g ? O2 0.247 moles 0.247 moles Mg x 1 mole O2 = 0.247x1/2 = moles O2 2 moles Mg

12
**Steps to Stoichiometry**

Convert mole to grams, particles or whatever the answer ask for. Calculate and write the answer. 2 Mg O2 MgO 3.00 g ? O2 0.247 moles moles 0.124 moles O2 x 32 g O2 = 0.124x32/1 = 3.97 g O2 1 moles O2

13
**Practice Stoichiometry**

Correct significant figures (sig figs) and rewrite the answer. 3.00 g Mg = 3 S.F. S.F. Answer: 3.97 g O2

14
Let’s Take It Slow…

Similar presentations

OK

Reaction Stoichiometry. Objectives Understand the concept of stoichiometry. Be able to make mass-to-mass stoichiometric calculations.

Reaction Stoichiometry. Objectives Understand the concept of stoichiometry. Be able to make mass-to-mass stoichiometric calculations.

© 2018 SlidePlayer.com Inc.

All rights reserved.

To ensure the functioning of the site, we use **cookies**. We share information about your activities on the site with our partners and Google partners: social networks and companies engaged in advertising and web analytics. For more information, see the Privacy Policy and Google Privacy & Terms.
Your consent to our cookies if you continue to use this website.

Ads by Google

Ppt on art of living download Ppt on conservation of environment for kids Presentations open ppt online Ppt on power grid failure video Ppt on information technology in agriculture Ppt on pc based industrial automation Ppt on data collection methods in healthcare Ppt on you can win if you want modern Ppt on brand equity management Ppt on carburetor repair