Presentation on theme: "ENGR-1100 Introduction to Engineering Analysis"— Presentation transcript:
1ENGR-1100 Introduction to Engineering Analysis Lecture 13
2Today Lecture Outline - Equilibrium equations in 2-D - Solving problems of equilibrium of a rigid body in 2-DFree body diagramApplication of physical laws- Statically indeterminate reaction and partial constraints
3Equilibrium Equations in 2-D The necessary and sufficient conditions for a body to be in equilibrium in 2-D (3 independent equations) are:‘A’ is ANY point on or off the rigid body.The moment equilibrium equation means that the resultant must pass through AThen apply the force equilibrium conditions along x and y to ensure that the resultant has zero magnitude (i.e. the body is in equilibrium)xyA
4Equilibrium Equations in 2-D: Alternate Forms ‘A’ and ‘B’ are points on a line NOT PERPENDICULAR to the x-axis.The condition MA=0 means that the resultantmust pass through A.The condition Rx=0 means that the resultant (ifother than zero) is perpendicular to the x-axis.Finally to MB=0 can only be satisfied if Ry=0.In other words:xyBALidMB=0Ry=0
5Equilibrium equations in 2D: Alternate Forms ‘A’ ,‘B’ and ‘C’ three non-collinear pointsThe condition MA=0 means that the resultantmust pass through A.The condition MB=0 means that the resultantmust pass through B. and thus must be along the line AB.Finally to MC=0 can only be satisfied if R=0 since C does not lie on AB.BCALid
6Special Force SystemsSpecial case 1. A “two force member” is a body which is actedon by only two forces. The forces are equal, opposite andcollinear (Newton’s Third Law!)FDon’t let the shape deceive youFFFA strut
7Special Force SystemsSpecial case 2. A “three force member” is a body which isacted on by only three forces. The forces MUST BECONCURRENT (otherwise there will be a resultant moment ofthe third force about the point of concurrency of the first two).F3F2F1
8Statically Determinate vs. Indeterminate Problems If the equilibrium equations are sufficient to determine all the support reactions, then the body is said to be statically determinate with adequate constraintsLidxyABHinge at ARoller at BxyAxAyByCan determine Ax, Ay and By from the 3 equilibrium equations
9Statically Determinate vs. Indeterminate Problems If a body has more supports than are necessary for equilibrium then the equilibrium equations alone are not sufficient to determine all the support reactions, then the body is said to be statically indeterminateStatically determinateStatically indeterminateyyxCxABALidBLidRoller at BRoller at BHinge at AHinge at A
10Problems with partial constraints Three support reactions in a 2D problem do not necessarily mean that the body is adequately constrained. Sometimes the body may be partially constrained and the equilibrium equations will not be sufficient to compute the support reactions.Statically determinateStatically indeterminate with inadequate constraintsyxyxABBRoller at BACannot determine Ax, Ay and Bx from the 3 equilibrium equationsHinge at A
11Problems with partial constraints A body with adequate number of reaction is improperly constrained when the constraints are arranged in such a way that the support forces are either concurrent or parallel.
12Example P6-40An angle bracket is loaded and supported as shown in Fig. P6-40.Determine the reactions at supports A and B.
13Solution First equation -350*0.22-500*0.1+Bx*0.2=0 x Known forces unknown forcesyAyAx500 N350 NBxBx=635 NSecond equation-Bx+500+ Ax=0Ax=135 NThird equationAy-350=0A= 135 i j NAy=350 N
14Class Assignment: Exercise set 6-38 please submit to TA at the end of the lectureA beam is loaded and supported as shown in Fig. P The beam has a uniform cross section and a mass of 20 kg. Determine the reaction at support A and the tension T in the cable.AyAxTAnswer:T= 512 NA= -293 i j N.
15Example P6-63GThe wrecker truck of Fig. P6-63 has a weight of 15,000 lb and a center of gravity at G. The force exerted on the rear (drive) wheels by the ground consists of both a normal component By and a tangential component Bx, while the force exerted on the front wheel consists of a normal force Ay only. Determine the maximum pull P the wrecker can exert when 0 = 30 if Bx, cannot exceed 0.8 By (because of friction considerations) and the wrecker does not tip over backward (the front wheels remain in contact with the ground).
17Bx=6.43 kip < kip=0.8* ByWhich satisfy the requirement for Bx <0.8 By
18Class Assignment: Exercise set 6-64 please submit to TA at the end of the lectureBar AB of Fig. P6-64 has a uniform cross section, a mass of 25 kg, and a length of 1m. Determine the angle q for equilibrium.Answer: q= 20.10