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Published byViolet Gray Modified over 8 years ago

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Homework Answers: Workbook page 2 1)N, W, Z, Q, R13) Assoc. (X)25) 8x – y – 3 2)I,R14) Comm. (X)26) -4c 3)I, R15) Add. Inverse27) -5r – 58s 4)W, Z, Q, R16) Mult. Inverse28) 4a + 1 5)Q, R17) Distributive29) -12 – 8x + 6y 6)Z, Q, R18) Add. Identity30) 13y 7)Z, Q, R19) -0.4, 2.5 or 5/231) (110t + 100) mi 8)Q, R20) 1.6, -0.625 or -5/8 32) false; counter- 9)Comm. (+)21) 11/16, -16/11 example: 10)Assoc. (+)22) -5 5/6, 6/35 5(1/5) is not > 11)Mult. Identity23) 3x 4(1/4) 12)Distributive24) -4a-16b

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Solving Equations with the Variable on Both Sides Objectives: to solve equations with the variable on both sides. to solve equations containing grouping symbols. A.1 Solve linear equations in one variable. A.1 Apply these skills to solve practical problems. A.3 Justify steps used in solving equations.

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To solve equations with variables on both sides: 1. Use the addition or subtraction property to move all variables to one side of the equal sign. 2. Solve the equation using the methods learned for previous equations.

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Let’s see a few examples: 1) 6x - 3 = 2x + 13 -2x -2x 4x - 3 = 13 +3 +3 4x = 16 4 4 x = 4 Be sure to check your answer! 6(4) - 3 =? 2(4) + 13 24 - 3 =? 8 + 13 21 = 21

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Let’s try another! 2) 3n + 1 = 7n - 5 -3n -3n 1 = 4n - 5 +5 +5 6 = 4n 4 4 Reduce! 3 = n 2 Check: 3(1.5) + 1 =? 7(1.5) - 5 4.5 + 1 =? 10.5 - 5 5.5 = 5.5

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Here’s a tricky one! 3) 5 + 2(y + 4) = 5(y - 3) + 10 Distribute first. 5 + 2y + 8 = 5y - 15 + 10 Next, combine like terms. 2y + 13 = 5y - 5 Now solve. (Subtract 2y.) 13 = 3y - 5 (Add 5.) 18 = 3y (Divide by 3.) 6 = y Check: 5 + 2(6 + 4) =? 5(6 - 3) + 10 5 + 2(10) =? 5(3) + 10 5 + 20 =? 15 + 10 25 = 25

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Let’s try one with fractions! 3 - 2x = 4x - 6 3 = 6x - 6 9 = 6x so x = 3/2 Steps: Multiply each term by the least common denominator (8) to eliminate fractions. Solve for x. Add 2x. Add 6. Divide by 6.

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Two special cases: 6(4 + y) - 3 = 4(y - 3) + 2y 24 + 6y - 3 = 4y - 12 + 2y 21 + 6y = 6y - 12 - 6y - 6y 21 = -12 Never true! 21 ≠ -12 NO SOLUTION! 3(a + 1) - 5 = 3a - 2 3a + 3 - 5 = 3a - 2 3a - 2 = 3a - 2 -3a -2 = -2 Always true! We write IDENTITY.

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Try a few on your own: 9x + 7 = 3x - 5 8 - 2(y + 1) = -3y + 1 8 - 1 z = 1 z - 7 2 4

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The answers: x = -2 y = -5 z = 20

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