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12 42 21 g = PO D g = 73.5 42 × 21 = 882 12 × g = 12g 12g = 882 ÷12.

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Presentation on theme: "12 42 21 g = PO D g = 73.5 42 × 21 = 882 12 × g = 12g 12g = 882 ÷12."— Presentation transcript:

1 12 42 21 g = PO D g = 73.5 42 × 21 = 882 12 × g = 12g 12g = 882 ÷12

2 1-7 Constant Rate of Change A rate of change is a rate that describes how one quantity changes in relation to another.

3 In a linear relationship, the rate of change between any two quantities is the same. A linear relationship has a constant rate of change.

4 Ex: A computer programmer charges customers per line of code written. Use the data table to calculate the constant rate of change. Lines of code 50100150200 Cost ($)1,0002,0003,0004,000 +50 +1,000 Change in dollars Change in lines Change in dollars Change in lines = = $1,000 50 lines $1,000 50 lines = = $20 1 line $20 1 line The constant rate of change per line of programming code is $20

5 The graph represents the distance traveled while driving on a highway. Find the constant rate of change. Ex: What does point (0, 0) represent? It means that in 0 hours the car drove 0 miles. What does point (2, 120) represent? It means that in 2 hours the car drove 120 miles.

6 The graph represents the distance traveled while driving on a highway. Find the constant rate of change. Ex: To find the rate of change, pick any two points on the line, such as (0,0) and (1,60). Change in miles Change in hours (60 – 0) miles (1 – 0) hours = = 60 miles 1 hour

7 The graph represents the distance traveled while driving on a highway. Find the constant rate of change. Ex: To find the rate of change, pick any two points on the line, such as (3,180) and (1,60). Change in miles Change in hours (180 – 60) miles (3 – 1) hours = = 120 miles 2 hours 60 miles 1 hour =

8 The graph represents the distance traveled while driving on a highway. Find the constant rate of change. Ex: 1.Pick 2 points 2.Find the difference between the y values and the difference between the x values. 3.Write as a rate. simplify


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