Download presentation

0
**INTRODUCTION TO INTEGRALS**

1
Section I The Basics

2
Antiderivatives If I ask you what is the derivative of x, you will say 1. If I ask you what is the antiderivative of x, and if you think I am asking you for the function such that the derivative of that function is x, then you are right. Now the derivative of what function is x? You might first guess it’s x2. However, the derivative of x2 is 2x, not x. So you might change x2 (just a bit) to ____ so that the derivative can be x. Now, what are the antiderivative of the following functions? 1. Antiderivative of 1 = _____ Antiderivative of x2 = _____ 3. Antiderivative of 1 + x2 = _____ Antiderivative of 4x3 = _____ 5. Antiderivative of 3x4 = _____ Antiderivative of xn = _____ 7. Antiderivative of kxn = _____ Antiderivative of cos x = _____ 9. Antiderivative of sin x = _____ 10. Antiderivative of sin x – cos x = _____

3
**Integrals—Notation and Definition**

Definition of the f(x) dx: We write and say the integral of f(x) is F(x) if the derivative of F(x) is f(x). F(x) is also called the antiderivative of f(x). For example, If you are asked for 2x dx? Ask yourself the derivative of what function yields 2x, and obviously, the function is x2 since the derivative of x2 is 2x. Therefore, 2x dx = x2. But wait… the derivative of functions such as x2 + 1, x and x2 is also 2x. So what is the 2x dx? As we can see, the antiderivative of 2x is not unique. Nevertheless, each of these functions contains ___ and they all differ by a _________. Therefore, we say 2x dx is _______ where C is a constant. Recall: Note: More examples: 3x – 2 dx = dx = cos x – sin x dx = sec 2 x + sec x tan x dx =

4
**Integrals—Definite vs. Indefinite**

There are mainly two types of integrals: definite integrals and indefinite integrals. Any other types are just subtypes of these two. What we did earlier is called indefinite integrals, which are also shown below on the left. The definite integrals are shown on the right. See if you can spot any difference between the two types? Indefinite Integrals vs. Definite Integrals? 1. x2 dx 2. cos x dx 3. 3t2 – 2t + 1 dt Terminology: is read as the (definite) integral of f from a to b, and in this notation, 1. is the integral sign (introduced by Leibniz, one of two cofounders of calculus; the other cofounder was _________) 2. The a and b are the limits of integration, where a is the ______ limit and b is the ______ limit. 3. f(x) is called the integrand. 4. The symbol, dx, only signifies the integration is with respect to x.

5
**How to Evaluate Definite Integrals**

Recall that if I ask you x2 dx? You say ________. Now how do we evaluate ? This is how: Example: More examples: Find the antiderivative function for the definite integral the same ways as if it’s an indefinite integral, only you don’t need to write the “+ C”. Plug the upper limit into the antiderivative function, then do the same for the lower limit. Subtract the two numbers from step 2, that will the answer to the definite integral.

6
**Section II Finding the Area of a Region**

7
**The Area of a Region Bounded by Straight-Line Curves**

Example 1: Find the area of the region bounded by the x-axis, the y-axis, and the lines y = 4 and x = 2. Example 2: Find the area of the region bounded by the x-axis, and the lines y = 2x and x = 2. Example 3: Find the area of the region bounded by the x-axis and the lines y = 2x, x = 1 and x = 2.

8
**The Area of a Region Bounded by Curves (At Least One is not Straight)**

Example: Find the area bounded by the x-axis, the curve y = x2 and the line x = 1.

9
**How to Improve the Approximation of the Area?**

Example: Find the area bounded by the x-axis, the curve y = x2 and the line x = 1. n = __ n = 32 n = 100 As we can see, even though the sum of the areas of the rectangles is always an ___________ of the area of the region, as the number of the rectangle increases, the sum of the areas of the rectangles is getting closer to the area of the region. The following table shows the sum of the area of the rectangles when n, the number of rectangles, is 2, 4, 8, 16, 100, 1,000, and 10,000. See if you can predict of the exact area of the region is? From the table, we can predict the exact area of the region is ______or ___.

10
**How Many Rectangles Do We Need?**

Example: Find the area bounded by the x-axis, the curve y = x2 and the line x = 1. As we can see, the more rectangles we use, the better the approximation for the area of the region. It is easy and feasible to calculate the total area of a couple of rectangles, however, it will be tedious and time consuming to calculate manually the area of a lot of rectangles (say 100, 1,000, 10,000, etc). Furthermore, to find the exact area of region, we must use ___________ many rectangles. How can we find the area of infinitely many rectangles? This is how: 1. We are dividing the region into n subdivisions, for each subdivision, we draw a rectangle. (When you draw the picture out, despite n can be any positive integer, choose n to be small, say 4 or 5). For each rectangle, we ask ourselves what the base and the height of the rectangle are. Notice that from one rectangle to next, while the base remains the same (it will be __ in this case, and in general, it will be _____), meanwhile, the ______ is changing because a non-constant function will have different heights at different x-values . Find the sum of the areas of the rectangles—it will be an expression in terms of n, and simplify this expression. In order to find the exact area of the region, take the limit as n approaches _________, because we need infinitely many rectangles to get the exact area of the region!

11
**Gosh, Is There a Short Way?**

Example: Find the area bounded by the x-axis, the y-axis, the curve y = x2 and the line x = 1. Yes, to find the exact area of region, just evaluate the definite integral of __ from __ to __, i.e., And in general, If the function f(x) is continuous and nonnegative on a closed interval [a, b], the exact area of region bounded by the x-axis, y = f(x), x = a and x = b is: More Examples: Find the area bounded by the x-axis, the curve y = x3 and the line x = 2. Find the area bounded by the x-axis, the curve , from x = 1 to x = 4. Find the area enclosed by the x-axis, f(x) = sin x from x = 0 to x = .

12
**Section III Different Ways to Approximate the Area of a Region**

13
**Right Endpoint Method vs. Left Endpoint Method**

In Section II, we learn to how approximate the area of a region (bounded by the x-axis, the curve y = x2 and the line x = 1) by using circumscribed rectangles. Hence, in some textbooks, this method is called Circumscribed Rectangles Method. However, in our textbook, it is called the Right Endpoint Method since the height of each rectangle is determined by the right endpoint after we subdivide the region into n intervals (see below for depiction when n = 4). Of course, if there is a Right Endpoint Method, there is a ____________ Method, in which case, the height of each rectangle will be determined by the __________ after we subdivide the region into n intervals (once again, let n = 4). Let’s find the approximate area:

14
**Right Endpoint Method vs. Left Endpoint Method (cont’d)**

Recall that the exact area of the region (bounded by the x-axis, the y-axis, the curve y = x2 and the line x = 1) is __. For n = 4 (i.e., 4 rectangles), the Right Endpoint Method (REM) yields an estimate of ___, which is an __________ of the exact area, whereas the Left Endpoint Method (LEM) yields an estimate of _____, which is an __________ of the exact area. However, to say REM is always an overestimate and LEM is always an underestimate is not correct, because it also depends on the graph of the function (or curve). For example, if the region is bounded by the x-axis, y = 1/x, and the lines x = 1 and x = 5, the REM will be an __________ of the exact area and LEM will be an ___________ of the exact area. REM: LEM: Furthermore, if the function is both increasing and decreasing on a closed interval, then we can’t tell whether the estimate by REM (or by LEM) is an overestimate or an underestimate. For example, the region is bounded by the x-axis, y = sin x from 0 to : REM: LEM:

15
**Other Methods: Midpoint Rule and “Average” Method**

sample points In the previous slides, we subdivide the region into sections and for each section we either take the left endpoint or the right endpoint to construct our rectangles. However, in general, it doesn’t matter—so long as, for a section, we pick a point that is on the curve. See diagram on the right (top). Such a point is called a sample point. It’s only because in math we want to do things systematically, that’s why we choose the left endpoints, or the right endpoints or the __________ as our sample points. See diagram on the right (below). When we construct the rectangles by sampling the midpoints, the method is called Midpoint Rule (MR). Example: Use MR and n = 4 to approximate the area of the bounded by the x-axis, the y-axis, the curve y = x2 and the line x = 1. Recall the exact area of the region is 1/3, so the Midpoint Rule (compared to LEM and REM) is by far the most accurate. However, if we have done the LEM and REM, (in this case, LEM = 7/32 and REM = 15/32), there is something we can do to these two numbers (without increasing n, the number of rectangles) to make the approximation more accurate. What is it?

16
**Can We Just Integrate—Why Do We Need These Approximation Rules?**

Recall that we can find the area of the region bounded by the x-axis, the curve y = x2 and the line x = 1, we just do: Why do we need to use REM (Right-Endpoint Method), LEM (Left-Endpoint Method) or MR (Midpoint Rule)? Each of these method is only an approximation of the area of the region, not the exact area (unless we use infinitely many rectangles). The reason is: Not every function can be easily integrated as x2. Some functions are difficult to integrate while some functions CAN’T be integrated. For example, 1. Find the area of the region bounded by the x-axis and y = x2 sin x from x = 0 to . 2. Find the area of the region bounded by the x-axis and y = esin x from x = 0 to 4.

17
**Section IV Area vs. Definite Integral**

18
**Does Definite Integral Always Yield the Area Under the Function?**

Example: Evaluate the integral . So the area under the function y = sin (2x) from 0 to is __? Yes! In a way, it is... Let’s look at the graph: Example: Find the area of the region bounded by the function y = sin (2x) and the x-axis from 0 to . Solution: If the area of any 2-dimensional region must be positive, simply using the definite integral will not give us the area of the region. Since the answer to the definite integral is 0 and we know the area can’t be 0! What should we do then? We still going to use definite integral to find its area, but we are not going to find it use one definite integral, instead we are going to use two of them (hint: divide the region into two subregions).

19
**Finding Area Bounded by a Function and the x-Axis**

Once again, to find the area bounded by a continuous function f(x) and the x-axis from a to b: If f(x) is positive (or nonnegative) on [a, b], then the area A = If f(x) is negative (or nonpositive) on [a, b], then the area A = or A = If f(x) is both positive and negative on [a, b], then (see the following): a b c1 c2 c3 A = or A= A = or A= a c b Therefore, if the problem asks for the evaluation of the definite integral of a function f(x) from a to b, there is no need to consider the graph of f—we just integrate and plug in the a and b . However, if the problem asks for the area bounded by f and the x-axis from a to b, not only we need to know the graph of f from a to b, but also we need to know the __________ of f between a and b. (In our textbook, the definite integral is the “net” area.) Example: 1. Evaluate: 2. Find the area bounded by x2 – 5x + 6 and the x-axis from x = 1 to x = 4.

20
**Finding Area Bounded by Two Functions**

If we have two continuous functions f(x) and g(x) with the property that f(x) g(x) on a closed interval [a, b], then the area bounded by these two functions from a to b is y = f(x) A = a b y = g(x) Example: Find the area bounded by f(x) = x2 and g(x) = x on [0, 1]. However, in general, if we have two continuous functions f(x) and g(x) on a closed interval [a, b], then the area bounded by these two functions from a to b (see below) y = g(x) y = f(x) A = a b Besides knowing the graph of the two functions, we also need to know their ____________ _______. To find it/them, we simply set the two functions equal to each other and solve for x. Example: Find the area bounded by f(x) = x3 and g(x) = x on [–1, 1].

21
**Finding Area Bounded by Two Curves**

There’s nothing in the book that says to find the area of a region bounded by two curves mans to integrate from x = a to b (i.e. , horizontally). We can integrate from y = c to d (i.e., vertically) if we want to. Furthermore, we need to integrate a region vertically if it is easier this way than integrating it horizontally. Example 1: Find the area bounded by y = x and d x = g(y) x = f(y) A = c Example 2: Find the area bounded by y = x, , y = 1 and the x-axis. Example 3: Find the area bounded by x = ½y2 – 3 and x = y + 1.

22
**Section V Volumes by Revolution**

23
**Volume by Revolving a Region under a Function (and Above the x-Axis)**

Example 1: Find the volume of a solid generated by revolving the region under f(x) = 3 from x = 0 to x = 4. Example 2: Find the volume of a solid generated by revolving the region under f(x) = x from x = 0 to x = 4. Example 3: Find the volume of a solid generated by revolving the region under f(x) = x2 from x = 0 to x = 2. Disk Method: If f(x) is continuous and nonnegative on [a, b], then the volume generated by revolving the region under f from a to b is: where f(x) is the ______ of a cross-section and [f(x)]2 is the ______ of the cross-section.

24
**Volume by Revolving a Region Between Two Functions**

Example 1: Find the volume of a solid generated by revolving the region between f(x) = x and g(x) = x from x = 0 to x = 1. Example 2: Find the volume of a solid generated by revolving the region between f(x) = x and g(x) = x from x = 1 to x = 4. Example 3: Find the volume of a solid generated by revolving the region under f(x) = x and g(x) = from x = 1 to x = 4. Washer Method: If f(x) and g(x) are continuous and nonnegative on [a, b] with f(x) g(x) on [a, b], then the volume generated by revolving the region between f and g from a to b is:

25
**Section VI Integration of Special Functions**

26
**Integral of Discontinuous Functions**

Recall that we can’t differentiate a function at the places where it’s discontinuous. However, we can integrate a function even it’s discontinuous. After all, integration of a function y = f(x) from x = a to b means to find the ________________________________________________. Example 1: Let Evaluate Example 2: Evaluate Note: Above, we only integrate functions with gaps, not with vertical asymptotes. We can evaluate integrals where the function has vertical asymptotes too. For example,

27
**Integral of Functions with Symmetries**

Recall that a function of y = f(x) may have symmetry with respect to (w.r.t.) the y-axis or the origin. If a function has symmetry w.r.t. to the y-axis, it’s called an ____ function. If a function has symmetry w.r.t. to the origin, it’s called an ____ function. So what? Knowing the function has one of the two above symmetries can reduce your work on the integral of the type where a > 0. How so? Note:

Similar presentations

OK

8 TECHNIQUES OF INTEGRATION. In defining a definite integral, we dealt with a function f defined on a finite interval [a, b] and we assumed that f does.

8 TECHNIQUES OF INTEGRATION. In defining a definite integral, we dealt with a function f defined on a finite interval [a, b] and we assumed that f does.

© 2018 SlidePlayer.com Inc.

All rights reserved.

Ads by Google

Ppt on paintings and photographs related to colonial period definition Ppt on producers consumers and decomposers video Free download ppt on indian culture Ppt online shopping presentation Ppt on diwali in hindi language Download ppt on turbo generator images Ppt on harvest festivals of india Ppt on odisha cultured Ppt on mid day meal programme Ppt on area of rectangle and square