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**Evaluating a Permutation**

EXAMPLE 3 Evaluating a Permutation Poetry Two students are chosen from a group of 6 to read the first and second poems at the school’s poetry reading. To find how many different ways the students can be chosen, find 6P2. 6P2 – = 6! (6 2)! 4! Use permutation formula. = Divide out common factors. = 30 Multiply. ANSWER The students can be chosen in 30 ways.

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GUIDED PRACTICE for Example 3 Find the number of permutations. P3 = 60 P6 = 720

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GUIDED PRACTICE for Example 3 P7 = 40, 320 P2 = 9, 900

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GUIDED PRACTICE for Example 3 10. What If? Suppose 3 students are chosen from a group of 8 to read in Example 3. In how many different ways can the students be chosen? To find how many different ways can the students be chosen, find 8P3 = 336 8P3

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