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Begin the slide show. An ant walks 2.00 m 25° N of E, then turns and walks 4.00 m 20° E of N. RIGHT TRIANGLE …can not be found using right-triangle math.

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Presentation on theme: "Begin the slide show. An ant walks 2.00 m 25° N of E, then turns and walks 4.00 m 20° E of N. RIGHT TRIANGLE …can not be found using right-triangle math."— Presentation transcript:

1

2 Begin the slide show.

3 An ant walks 2.00 m 25° N of E, then turns and walks 4.00 m 20° E of N. RIGHT TRIANGLE …can not be found using right-triangle math because WE DON’T HAVE A RIGHT TRIANGLE! 4.00 m 2.00 m dtdt CONSIDER THE FOLLOWING... The total displacement of the ant…

4 An ant walks 2.00 m 25° N of E, then turns and walks 4.00 m 20° E of N. This can’t be solved using our right-triangle math because it isn’t a RIGHT TRIANGLE! We can add the two individual displacement vectors together by first separating them into pieces, called x- & y-components The total displacement of the ant…

5 1) A vector with a -x component and a +y component…

6 2) A vector with a +x component and a - y component…

7 3) A vector with a +x component and a +y component…

8 4) A vector with a -x component and a - y component…

9 5) A vector with a -x component and a zero y component…

10 6) A vector with a zero x component and a -y component…

11 7) For the vector 1350 ft, 30° N of E… R = 1350 ft θ = 30°

12 8) For the vector 14.5 km, 20° W of S… R = 14.5 km θ = 70°

13 9) For the vector 2400 m, S… R = 2400 m θ = 90°

14 An ant walks 2.00 m 25° N of E, then turns and walks 4.00 m 20° E of N. 4.00 m 2.00 m dtdt This was the situation... The total displacement of the ant… R 1 = 2.00 m, 25° N of E R 2 = 4.00 m, 20° E of N

15 R 1 = 2.00 m, 25° N of E 25° x = R cosθ = (2.00 m) cos 25° = +1.81262 m y = R sinθ = (2.00 m) sin 25° = +0.84524 m 1.81262 m 0.84524 m

16 R 2 = 4.00 m, 20° E of N x = R cosθ = (4.00 m) cos 70° = +1.36808 m y = R sinθ = (4.00 m) sin 70° = +3.75877 m 1.36808 m 3.75877 m θ = 70˚

17 So, you have broken the two individual displacement vectors into components. Now we can add the x-components together to get a TOTAL X- COMPONENT; adding the y- components together will likewise give a TOTAL Y-COMPONENT. Let’s review first…

18 R 1 = 2.00 m, 25° N of E 25° x = R cosθ = (2.00 m) cos 25° = +1.81262 m y = R sinθ = (2.00 m) sin 25° = +0.84524 m 1.81262 m 0.84524 m

19 R 2 = 4.00 m, 20° E of N x = R cosθ = (4.00 m) cos 70° = +1.36808 m y = R sinθ = (4.00 m) sin 70° = +3.75877 m 1.36808 m 3.75877 m

20 We have the following information: xy R1R2R1R2 +1.81262 m +1.36808 m +0.84524 m +3.75877 m

21 Now we have the following information: xy R1R2R1R2 +1.81262 m +1.36808 m +0.84524 m +3.75877 m Adding the x-components together and the y- components together will produce a TOTAL x- and y-component; these are the components of the resultant.

22 xy R1R2R1R2 +1.81262 m +1.36808 m +0.84524 m +3.75877 m +3.18070 m +4.60401 m x-component of resultanty-component of resultant

23 Now that we know the x- and y- components of the resultant (the total displacement of the ant) we can put those components together to create the actual displacement vector. 3.18070 m 4.60401 m dTdT θ

24 The Pythagorean theorem will produce the magnitude of d T : c 2 = a 2 + b 2 (d T ) 2 = (3.18070 m) 2 + (4.60401 m) 2 d T = 5.59587 m  5.60 m A trig function will produce the angle, θ: tan θ = (y/x) θ = tan -1 (4.60401 m / 3.18070 m) = 55º

25 Of course, ‘55º’ is an ambiguous direction. Since there are 4 axes on the Cartesian coordinate system, there are 8 possible 55º angles. 55º 55° …and there are 4 others (which I won’t bother to show you). To identify which angle we want, we can use compass directions (N,S,E,W)

26 3.18070 m 4.60401 m dTdT θ From the diagram we can see that the angle is referenced to the +x axis, which we refer to as EAST. The vector d T is 55° north of the east line; therefore, the direction of the d T vector would be 55° North of East

27 So, to summarize what we just did…

28 We started with the following vector addition situation… 4.00 m 2.00 m dtdt …which did NOT make a right triangle.

29 dtdt Then we broke each of the individual vectors ( the black ones) into x- and y-components… …and added them together to get x- and y- components for the total displacement vector. And now we have a right triangle we can analyze!

30

31 Yeah, baby! Let’s give it a try! Complete #16 on your worksheet. (Check back here for the solution to the problem when you are finished.)

32 # 16 (continued on next slide) (west) (south) (east) (north) (west)(south)

33 (west)(south)


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