Presentation on theme: "Ionization energy is the energy required to REMOVE an electron from an atom in the gas phase Atom in ground state (g) Atom + (g) + e - Always positive."— Presentation transcript:
Ionization energy is the energy required to REMOVE an electron from an atom in the gas phase Atom in ground state (g) Atom + (g) + e - Always positive values measured in kJ/mol or eV/atom Besides hydrogen, atoms have a series of ionization energies because more than one electron can be removed
First ionization energies generally DECREASE down a column Group showing off trends.
The electron removed is increasingly farther from the nucleus, thus reducing the nucleus- electron attractive force
Inner electrons at lower energy levels "shield" the valence electrons from the nucleuss force of attraction (Z*- effective nuclear charge). As each element of the group has more energy levels, the subshells decrease Z* for the electrons in the outer shell, making it easier to remove them.
First ionization energies generally INCREASE left to right across a period Periodic Trends
The number of protons increases from left to right; therefore, the Z* (effective nuclear charge) is greater to the right of a period. The electron experiences a greater electrostatic attraction to the nucleus, and as a result, more energy is needed to remove it.
Although inaccurate, the Bohr model serves as a good visual.
First ionization energies from left to right across this period generally increases. But Boron and Oxygen dont follow this trend! Why?
Be: [He] 2s 2 vs. B: [He] 2s 2 2p 1 When Boron is ionized, a 2p electron (slightly higher energy with smaller Z*) is removed, requiring less energy This small dip in the increasing trend occurs between the other Group 2A and Group 3A elements
Oxygens first ionization energy < Nitrogen Electrons are assigned to separate p- orbitals (minimizing the force of repulsion) in elements of Group 3A~5A, like nitrogen In elements of Group 6A, such as oxygen, the paired electrons increase repulsion, leading for easier removal But beyond the first pair, Z* outweighs electron repulsion and the increasing trend continues for Group 7A and on
Elements form ions with different charges because of ionization energies! Notice the huge differences between the first and second IEs of Na, the second and third IEs of Mg, and so on
Removing the one electron from Nas 3s- orbital doesnt require much energy, but breaking into the filled 2p-orbital will require much, much more! The same huge jump occurs after removing the 3s 2 electrons from Mg and the 3s 2 and 3p 1 electrons from Al The enormous gap between higher ionization energies explains why Main Group element ions have the same charge as you go down the group