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F=BIL Or is it….. F=qvB Also Determine the direction of the Force!
B V Positive Charge is moving
Use: F=qvB Force is going:
B V Negative Charge is moving
Use: F=qvB Force is going: Coming out of the page!
Use: F=BiL Force is going:
F = 1.5x N V = 2.0x10 7 m/s B = ? Electron
Use: F=qvB 1.5 x = (1.6 x C) x (2.0x10 7 m/s) x B B= T Force is going:
B =.15 T V = 1.5x10 6 m/s F = ? Electron
You would break your hand trying this one so the charge will not feel any force
B =.75 T What is the acceleration of the proton? Mass of a proton is = × kilograms V = 5.8x10 6 m/s Proton
Use: F=qvB F=ma ma=qvB ( × kg)x a = (1.6 x C) x (5.8x10 6 m/s) x.75 T a = x m/s/s Force is going:
B =.75 T 1. What is the acceleration of the electron? V = 4.5x10 7 m/s 2. What is the radius of curvature? Hint: a c = v 2 /r Electron
Use: F=qvB F=mv 2 /r mv 2 /r=qvB (9.11 × kg)(4.5x10 7 m/s) 2 /r= (1.6 x C) x (4.5x10 7 m/s) x.75 T r = 3.4 x m Force is going:
F=BIL Or is it….. F=qvB. B V The force is to the left.
Page 1. The approach of the magnet makes the B field inside the 3.0 cm diameter loop go from.025 T to.175 T in.0035 s. What is the EMF, direction of the.
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DIVIDING INTEGERS 1. IF THE SIGNS ARE THE SAME THE ANSWER IS POSITIVE 2. IF THE SIGNS ARE DIFFERENT THE ANSWER IS NEGATIVE.
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