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F=BIL Or is it….. F=qvB Also Determine the direction of the Force!
V B Positive Charge is moving
Use: F=qvB Force is going:
V B Negative Charge is moving
Use: F=qvB Force is going: Coming out of the page!
Use: F=BiL Force is going:
F = 1.5x10-12 N V = 2.0x107 m/s Electron B = ?
Use: F=qvB 1.5 x 10-12= (1.6 x 10-19C) x (2.0x107 m/s) x B B= T Force is going:
B = .15 T Electron V = 1.5x106 m/s F = ?
You would break your hand trying this one so the charge will not feel any force
B = .75 T What is the acceleration of the proton?Mass of a proton is = × kilograms B = .75 T Proton V = 5.8x106m/s
Use: F=qvB F=ma ma=qvB ( × kg)x a = (1.6 x 10-19C) x (5.8x106m/s) x .75 T a = x 1014 m/s/s Force is going:
B = .75 T 1. What is the acceleration of the electron?2. What is the radius of curvature? Hint: ac = v2/r Electron V = 4.5x107m/s
Use: F=qvB F=mv2/r mv2/r=qvB (9.11 × kg)(4.5x107m/s)2/r= (1.6 x 10-19C) x (4.5x107m/s) x .75 T r = 3.4 x 10-4 m Force is going:
F=BIL Or is it….. F=qvB.
Page 1. The approach of the magnet makes the B field inside the 3.0 cm diameter loop go from.025 T to.175 T in.0035 s. What is the EMF, direction of the.
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